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JavaScript to PHP [message #185019] Mon, 24 February 2014 11:02 Go to next message
Stan Weiss is currently offline  Stan Weiss
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Over the years I have written a number of JavaScript. The past couple of
years I have been rewriting a few in PHP. I do not have any good PHP
reference material. Can someone help me out. What would I replace
Math.POW with?

ans1 = c7 + c8 + c9 + c10 + c11
c12 = ( Math.pow(10.0, ans1))

Thanks,
Stan
Re: JavaScript to PHP [message #185020 is a reply to message #185019] Mon, 24 February 2014 11:16 Go to previous messageGo to next message
Christoph Michael Bec is currently offline  Christoph Michael Bec
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Stan Weiss wrote:

> Over the years I have written a number of JavaScript. The past couple of
> years I have been rewriting a few in PHP. I do not have any good PHP
> reference material.

Well, you can use the PHP manual.[1]

> Can someone help me out. What would I replace
> Math.POW with?
>
> ans1 = c7 + c8 + c9 + c10 + c11
> c12 = ( Math.pow(10.0, ans1))

Just use the pow() function.[2] Since PHP 5.6 there's even an operator
(**) available.[3]

[1] <http://www.php.net/manual/>
[1] <http://www.php.net/manual/function.pow.php>
[2] <https://wiki.php.net/rfc/pow-operator>

--
Christoph M. Becker
Re: JavaScript to PHP [message #185023 is a reply to message #185020] Mon, 24 February 2014 12:27 Go to previous messageGo to next message
Thomas 'PointedEars'  is currently offline  Thomas 'PointedEars'
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Christoph Michael Becker wrote:

> Stan Weiss wrote:
>> Can someone help me out. What would I replace
>> Math.POW with?
>>
>> ans1 = c7 + c8 + c9 + c10 + c11
>> c12 = ( Math.pow(10.0, ans1))
>
> Just use the pow() function.[2] Since PHP 5.6 there's even an operator
> (**) available.[3]

The latest stable PHP version is 5.5.9. [1] PHP 5.6.0*alpha2* was released
on 2014-02-13. [2] It is not a good idea to speak of future software
versions as something that is carved in stone.

[1] <http://php.net/downloads>
[2] <http://php.net/>

> [2] <https://wiki.php.net/rfc/pow-operator>

You got your footnotes mixed.


PointedEars
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Re: JavaScript to PHP [message #185024 is a reply to message #185023] Mon, 24 February 2014 13:47 Go to previous messageGo to next message
Christoph Michael Bec is currently offline  Christoph Michael Bec
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Thomas 'PointedEars' Lahn wrote:

> Christoph Michael Becker wrote:
>
>> Stan Weiss wrote:
>>> Can someone help me out. What would I replace
>>> Math.POW with?
>>>
>>> ans1 = c7 + c8 + c9 + c10 + c11
>>> c12 = ( Math.pow(10.0, ans1))
>>
>> Just use the pow() function.[2] Since PHP 5.6 there's even an operator
>> (**) available.[3]
>
> The latest stable PHP version is 5.5.9. [1] PHP 5.6.0*alpha2* was released
> on 2014-02-13. [2] It is not a good idea to speak of future software
> versions as something that is carved in stone.

ACK. I should have used at least future tense.

> [1] <http://php.net/downloads>
> [2] <http://php.net/>
>
>> [2] <https://wiki.php.net/rfc/pow-operator>
>
> You got your footnotes mixed.

Sorry.

--
Christoph M. Becker
Re: JavaScript to PHP [message #185098 is a reply to message #185020] Wed, 26 February 2014 09:36 Go to previous message
Stan Weiss is currently offline  Stan Weiss
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Christoph,
Thank You.

Stan


Christoph Michael Becker wrote:
>
> Stan Weiss wrote:
>
>> Over the years I have written a number of JavaScript. The past couple of
>> years I have been rewriting a few in PHP. I do not have any good PHP
>> reference material.
>
> Well, you can use the PHP manual.[1]
>
>> Can someone help me out. What would I replace
>> Math.POW with?
>>
>> ans1 = c7 + c8 + c9 + c10 + c11
>> c12 = ( Math.pow(10.0, ans1))
>
> Just use the pow() function.[2] Since PHP 5.6 there's even an operator
> (**) available.[3]
>
> [1] <http://www.php.net/manual/>
> [1] <http://www.php.net/manual/function.pow.php>
> [2] <https://wiki.php.net/rfc/pow-operator>
>
> --
> Christoph M. Becker
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