| Re: Filling an array with random input doesn't quite work [message #185243 is a reply to message #185242] |
Fri, 14 March 2014 15:47   |
Norman Peelman
Messages: 126
Registered: September 2010
Karma:
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Senior Member |
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On 03/14/2014 11:00 AM, Jerry Stuckle wrote:
> On 3/14/2014 9:31 AM, Norman Peelman wrote:
>> On 03/12/2014 11:11 PM, Jerry Stuckle wrote:
>>> On 3/12/2014 11:02 PM, Norman Peelman wrote:
>>>> On 03/12/2014 01:18 PM, richard wrote:
>>>> > $x=1;
>>>> > while ($x<40){
>>>> > $yr=range(60,69);
>>>> > shuffle($yr);
>>>> > $ayr[$x]=$yr[$x];
>>>> > echo $ayr[$x]."<br>";
>>>> > $x++;
>>>> > }
>>>> >
>>>> >
>>>> > I am attempting to load an array based upon the range of numbers 60
>>>> > through
>>>> > 69.
>>>> > The array will have 40 items.
>>>> > This code produces 9 items just fine.
>>>> > The rest of the array is empty.
>>>> > What am I missing?
>>>> >
>>>>
>>>> for ($items=1; $items<=40; $items++)
>>>> {
>>>> $ayr[$items] = range(60,69);
>>>> shuffle(&$ayr[$items]);
>>>> }
>>>>
>>>>
>>>
>>> Why would you shuffle a single item?
>>>
>>>
>>
>> $ayr[$items] is an Array
>>
>> php > print_r($ayr);
>> Array
>> (
>> [1] => Array
>> (
>> [0] => 60
>> [1] => 61
>> [2] => 62
>> [3] => 63
>> [4] => 64
>> [5] => 65
>> [6] => 66
>> [7] => 67
>> [8] => 68
>> [9] => 69
>> )
>>
>> )
>>
>> ... after Shuffle:
>>
>> php > shuffle(&$ayr[1]);
>> php > print_r($ayr[1]);
>> Array
>> (
>> [0] => 67
>> [1] => 69
>> [2] => 66
>> [3] => 61
>> [4] => 62
>> [5] => 60
>> [6] => 64
>> [7] => 68
>> [8] => 63
>> [9] => 65
>> )
>>
>>
>>
>
> Sorry, I was in a hurry and wasn't paying as much attention.
>
> But then why have 40 different arrays of 10 items each, anyway?
>
I don't even know why there are 40 items when you are pulling from a
selection of 10 - there's going to be duplicates. Maybe that doesn't
matter... I think someone else actually had what Richard was really after.
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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