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php include question [message #172149]

Wed, 02 February 2011 00:14

Bill[1]
Messages: 1
Registered: February 2011

Karma:

Junior Member

I have many (hundreds) html files that I need to put some logic to
check whether the user logged in or not. So I add php code to check
the cookie, which is set when the user sign in. The following is the
sample php file.

============================================================
<?php
if ( (!isset($_COOKIE['uid'])) )
{
?>
<html><head><title>you are not logged in</title></head><body>
You are not logged in so you are not able to access this resource. </
br>
</body></html>
<?php
}
else
{
?>

<html>
<head>
<title>Logged in</title>
</head>
<body>
you are logged in and the resources is here and blah blah...

</body>
</html>

<?php } ?>

====================================================
I am trying to create a header.php with the first lines all the way to
the 
and then include it in the other php files.

The reason I want to create a header.php file is that the real logic
is actually more complex than this example. I will need to only
change one file instead of hundereds or thousands files when we need
to change the logic. And also for the new pages, I can ask the
developer to add only one line in each of the html file like:
<?php include('header.php'); ?>

But when I access the php file which includes the header.php, in the
error log, it says:

PHP Parse error: syntax error, unexpected $end in /var/www/html/
library/header.php on line 13
I know that is probably because in the header.php the if - else is
not closed yet. Here come my questions:

1) any good way to do what we want to do?
2) seems to me that the included php file should be logically self-
contained? - in the example, the if - else logic is split into two
files...

Thanks.

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[Message index]

		php include question By: Bill[1] on Wed, 02 February 2011 00:14
		Re: php include question By: Jerry Stuckle on Wed, 02 February 2011 00:42
		Re: php include question By: alvaro.NOSPAMTHANX on Wed, 02 February 2011 08:15

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