| Re: populate pulldownbox from query [message #174090 is a reply to message #174088] |
Sat, 21 May 2011 12:08   |
Co
Messages: 75
Registered: May 2011
Karma:
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On 21 mei, 13:00, t...@mountifield.org (Tony Mountifield) wrote:
> In article <cddfd7a4-dfb5-48c0-8ecc-e2c86baaf...@glegroupsg2000goo.googlegroups.com>,
>
> Co <comp(dot)lang(dot)php(at)googlegroups(dot)com> wrote:
>> I don't think the formatting is the problem.
>> The problem is that the values are not set in the pulldownbox.
>> It does populate the box with the names but the value from the database
>> for the current record is not displayed.
>
>> Marco
>
> What you need to do, within the loop that outputs the <option> elements,
> is to check the value(s) in the row to see if this is the element that
> should be currently displayed, and it so, you need to add the "selected"
> tag to the <option> element, e.g.
>
> <option id="$id" selected>$optiontext</option>
>
> For all other options, omit the "selected".
>
> Cheers
> Tony
> --
> Tony Mountifield
> Work: t...@softins.co.uk -http://www.softins.co.uk
> Play: t...@mountifield.org -http://tony.mountifield.org
Tony,
I changed my code and now it does load the names and give me the
current partner in the field.
<?php
$query="SELECT id, firstname, lastname, rank FROM myMembers WHERE id
<> $id ORDER BY lastname";
$result = mysql_query ($query);
echo "<select name=partner class=formFields id=partner
value=''>Partner</option>";
while($nt=mysql_fetch_array($result)){//Array or records stored in $nt
echo "<option id=$id selected>{$nt['rank']} {$nt['firstname']}
{$nt['lastname']}</option>";
//echo "<option value=$nt[id]>{$nt['rank']} {$nt['firstname']}
{$nt['lastname']} </option>";
/* Option values are added by looping through the array */
}
echo "<option value='$partner'>{$nt['rank']} {$nt['firstname']}
{$nt['lastname']}</option>";
echo "</select>";// Closing of list box
?>
Only problem is that I can't seem to update the field anymore.
Marco
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