[newbie] datetime issues [message #174369] |
Wed, 08 June 2011 22:54 |
Jeff[1]
Messages: 2 Registered: June 2011
Karma: 0
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Junior Member |
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hi
php 5
I'm trying to construct an sql query where I need to filter between 2 dates.
So how do I dynamically create those datetime values?
Tip: The day value will always be 1 (or 01 ?).
I will dynamically select values from the entire last month.
I tryed this:
convert('2012-'.date('m').'-01 00:00:00',DATETIME)
which gave me syntax error and also I need to some more if testing on year.
So hope there is a better way of doing this
please help me
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Re: [newbie] datetime issues [message #174370 is a reply to message #174369] |
Thu, 09 June 2011 00:12 |
sheldonlg
Messages: 166 Registered: September 2010
Karma: 0
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Senior Member |
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On 6/8/2011 6:54 PM, Jeff wrote:
> hi
>
> php 5
>
> I'm trying to construct an sql query where I need to filter between 2 dates.
> So how do I dynamically create those datetime values?
>
> Tip: The day value will always be 1 (or 01 ?).
>
> I will dynamically select values from the entire last month.
>
> I tryed this:
> convert('2012-'.date('m').'-01 00:00:00',DATETIME)
> which gave me syntax error and also I need to some more if testing on year.
> So hope there is a better way of doing this
>
> please help me
What do you mean by "from the entire last month"? The expression you
have will give for June, for example, '2012-06-01 00:00:00' which is
already in DATETIME format (which I assume is how your data are stored
in that column). So, if you want everything from the first of June it
would be
$sql ="SELECT WHATEVER FROM WHEREVER ";
$sql .= "WHERE THE_COL_NAME >= '2012-" . date('m') . "-01 00:00:00'";
Note that the final value of $sql in this case, for June, would be
SELECT WHATEVER FROM WHEREVER WHERE
THE_COL_NAME >= '2012-06-01 00:00:00'
--
Shelly
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