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Re: error message I don understand [message #174928 is a reply to message #174926] Mon, 18 July 2011 16:01 Go to previous messageGo to previous message
The Natural Philosoph is currently offline  The Natural Philosoph
Messages: 993
Registered: September 2010
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Thomas 'PointedEars' Lahn wrote:
> Denis McMahon wrote:
>
>> Thomas 'PointedEars' Lahn wrote:
>>> In the end an oversimplified, wrong explanation. It is a syntactical
>>> requirement, not a functional one:
>>>
>>> $a = x();
>> Here you're assigning the return value of the function x() to the
>> variable $a.
>>
>>> $a[0] = 42;
>> Here you're writing to the variable $a (or rather, in this case, to an
>> element of the array that is variable $a).
>>
>> Neither of these is trying to assign (write) a value to the return value
>> of the function call.
>
> Yes, it is. The return value of the function is a one-element array, and
> with that assignment I am writing to the same memory area (or another memory
> area that holds a copy of the former's content) by changing the first
> element of the array. IOW, the return value is _not_ read-only.
>
>> Whether you call the issue syntactical or not is just irrelevant and
>> messing about with semantics.
>
> You are mistaken. The issue is a syntactical one, not a functional one,
> because a function call (currently) cannot occur on the left-hand side of an
> assignment expression in PHP, *regardless* of the return value of function
> to be called.
>

so you are saying that (x())[3]=7; is not allowable?

> IOW, it does not make sense to say that "the return value is read-only" as
> the function is *never* *called* and *no* return value is obtained in the
> first place then. This is a rather important difference because syntax
> errors are detected by the parser upon (JIT-)compilation already.
>
>
> PointedEars

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