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Re: OT: and even in Dart .........Re: simple session question [message #175715 is a reply to message #175714] Sat, 22 October 2011 15:54 Go to previous messageGo to previous message
The Natural Philosoph is currently offline  The Natural Philosoph
Messages: 993
Registered: September 2010
Karma:
Senior Member
Luuk wrote:
> On 22-10-2011 17:08, Luuk wrote:
>> On 22-10-2011 16:37, The Natural Philosopher wrote:
>>> The Natural Philosopher wrote:
>>>> Luuk wrote:
>>>> > On 22-10-2011 01:32, The Natural Philosopher wrote:
>>>> >> try $foo=($foo++);
>>>> >>
>>>> >> But actually, why not just
>>>> >>
>>>> >> $foo+=1;
>>>> >
>>>> > Because they differ?
>>>> >
>>>> > $ php -r ' $foo=0; $foo=$foo++; print $foo."\n";'
>>>> > 0
>>>> > $ php -r ' $foo=0; $foo=($foo++); print $foo."\n";'
>>>> > 0
>>>>
>>>> That is surely a bug..
>>>>
>>>
>>> viz
>>>
>>> ~$ cat test.c
>>> #include <stdio.h>
>>> main()
>>> {
>>> int foo;
>>> foo=0;
>>> foo=(foo++);
>>> printf("%d\n",foo);
>>> }
>>> ~$ ./test
>>> 1
>>>
>>>
>>> I thought PHP followed C operator precedence exactly..
>>>
>>>
>>
>> it seems to follow PERL
>>
>> $ perl -e '$foo=0; $foo=$foo++; print $foo."\n";'
>> 0
>> $ perl -e '$foo=0; $foo=($foo++); print $foo."\n";'
>> 0
>> $ perl -e '$foo=0; $foo++; print $foo."\n";'
>> 1
>> $
>>
>>
>
> see: http://www.dartlang.org
>
> main() {
> int foo=0;
> foo=foo++;
> print('First test: ${foo}');
>
> foo=0;
> foo=(foo++);
> print('Second test: ${foo}');
>
> foo=0;
> foo++;
> print('Third test: ${foo}');
>
> }
>
> which gives:
> First test: 0
> Second test: 0
> Third test: 1
>
>

still a bug in PHP where

"Parentheses may be used to force precedence, if necessary. For
instance: (1 + 5) * 3 evaluates to 18"

(from the manual)

I THOUGHT the general rule was that the value of (entity) was always the
FINAL value after ALL internal operations had been carried out.

Agreed its a crappy way to code, which is probably why no one has
noticed it.

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