| Re: preg_match() oddities and question [message #176088 is a reply to message #176077] |
Wed, 23 November 2011 08:55   |
Sandman
Messages: 32
Registered: August 2011
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In article <3004614(dot)SPkdTlGXAF(at)PointedEars(dot)de>,
Thomas 'PointedEars' Lahn <PointedEars(at)web(dot)de> wrote:
>>>> So I have this regexp:
>>>>
>>>> if (preg_match("/^(.*?)\s*(\d*?)\s*([A-Z,a-z,-]*?)$/", $search, $m)){
>>>> $streetname = uc_words($m[1]);
>>>> $streetnumber = trim($m[2]);
>>>> $streetletter = strtoupper($m[3]);
>>>> $search = trim($streetname . SPACE . $streetnumber .
>>>> $streetletter);
>>>> }
>>>>
>>>> The desired result is taki9ng the input ($search) and split it into
>>>> its parts as an address, right? $search can be, for example, "foo
>>>> street 34", "longstreet 45b", "longstreet 45 b" or just "longstreet".
>>>
>>> "10 East 42nd Street, New York, NY 10017, USA".
>>
>> That wouldn't be a normal swedish address, no. :)
>
> You had not limited the country or the language of your street addresses.
Well, to my defense, the subject line was "preg_match() and swedish
characters" until I changed it. I hadn't changed it when I wrote my
examples.
> My point is that parsing a street name and a house number from a street
> address is a hard problem that cannot be solved only by applying one regular
> expression.
Right, but your example is not a valid argument for that conclusion.
My examples contained the variations of addresses that I wanted to
match. Or are you saying that there is no way to use regular
expressions to catch the examples I gave? Because I have a hard time
believing that.
--
Sandman[.net]
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