| Re: Implied cast differs from explicit cast [message #176708 is a reply to message #176707] |
Thu, 19 January 2012 12:39   |
Arno Welzel
Messages: 317
Registered: October 2011
Karma:
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Senior Member |
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Arno Welzel, 2012-01-19 13:36:
> Jerry Stuckle, 2012-01-17 14:16:
>
>> On 1/17/2012 12:59 AM, Arno Welzel wrote:
>>> Jerry Stuckle, 2012-01-16 14:45:
>>>
>>>> On 1/16/2012 8:28 AM, The Natural Philosopher wrote:
>>>> > lb wrote:
>>>> >> jstucklex(at)attglobal(dot)net wrote:
>>>> >>> ...
>>>> >>> No, it is not. '0x12' is a hex number, not an integer. (int)'0x12'
>>>> >>> converts this correctly to 0.
>>>> >
>>>> > Looks like Jerry doesn't know what an integer is either.
>>>> >
>>>> > A hex number of course *is* an integer, unless its a hex representation
>>>> > of floating point.
>>>> >
>>>> > Killfile the prat like I have.
>>>> >
>>>> >
>>>>
>>>> 0x12 is not an integer. It is a hexadecimal value.
>>>
>>> No, 0x12 (and *not* "0x12") is the hexadecimal *representation* of the
>>> value 18. There is no thing like "hexadecimal value" and "0x12" is a
>>> *string* and not a number at all.
>>>
>>
>> No, it is a hexadecimal value. It may be an integer, it may be a
>> character, it may be a set of flags... It does not have to be an integer.
>>
>>> In fact PHP only knows to types of numbers: integers and floating point.
>>> There is no "hexadecimal" data type.
>>>
>>
>> Excuse me - there is. See hexdec().
>
> <http://php.net/manual/en/function.hexdec.php>
>
> You don't know what a data type is? Do you?
>
> See <http://www.php.net/manual/en/language.types.php> and show me, where
> the "hexadecimal data type" is explained.
And you should read the section about *integer* literal in
<http://www.php.net/manual/en/language.types.integer.php> very carefully.
There is no thing as "conversion of hexadecimal values to an integer".
EOD for me.
--
Arno Welzel
http://arnowelzel.de
http://de-rec-fahrrad.de
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