| Re: Reading & Displaying Latex Rendered images [message #178560 is a reply to message #178557] |
Mon, 02 July 2012 08:10   |
Fastian
Messages: 20
Registered: June 2012
Karma:
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Junior Member |
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On Monday, July 2, 2012 12:34:33 PM UTC+5, Álvaro G. Vicario wrote:
> El 02/07/2012 8:42, Fastian escribió/wrote:
>> <?
>> $image = file_get_contents('users.gif');
>>
>> header('Content-Type: image/gif');
>>
>> //imagegif($image); // I also tried to display image with imagegif but it also didnt work.
>
> The imagegif() function [1] expects «An image resource, returned by one
> of the image creation functions, such as imagecreatetruecolor()». I
> don't know how you reached the conclusion that you need such functions,
> given that are not even using PHP to generate the image :-?
>
> Probably, readfile() is all you need.
>
>
> [1] http://php.net/imagegif
> [1] http://php.net/readfile
>
>> But the image is NOT displayed on the browser.Where I am wrong?
>
> Browsers are basically designed to ignore invalid stuff and your
> "testing.php" script is possibly printing an error message rather than a
> valid GIF file. I suggest you remove the last layer and debug
> "testing.php" directly.
>
>
>
>
> --
> -- http://alvaro.es - Álvaro G. Vicario - Burgos, Spain
> -- Mi sitio sobre programación web: http://borrame.com
> -- Mi web de humor satinado: http://www.demogracia.com
> --
On Monday, July 2, 2012 12:34:33 PM UTC+5, Álvaro G. Vicario wrote:
> El 02/07/2012 8:42, Fastian escribió/wrote:
>> <?
>> $image = file_get_contents('users.gif');
>>
>> header('Content-Type: image/gif');
>>
>> //imagegif($image); // I also tried to display image with imagegif but it also didnt work.
>
> The imagegif() function [1] expects «An image resource, returned by one
> of the image creation functions, such as imagecreatetruecolor()». I
> don't know how you reached the conclusion that you need such functions,
> given that are not even using PHP to generate the image :-?
>
> Probably, readfile() is all you need.
>
>
> [1] http://php.net/imagegif
> [1] http://php.net/readfile
>
>> But the image is NOT displayed on the browser.Where I am wrong?
>
> Browsers are basically designed to ignore invalid stuff and your
> "testing.php" script is possibly printing an error message rather than a
> valid GIF file. I suggest you remove the last layer and debug
> "testing.php" directly.
>
>
>
>
> --
> -- http://alvaro.es - Álvaro G. Vicario - Burgos, Spain
> -- Mi sitio sobre programación web: http://borrame.com
> -- Mi web de humor satinado: http://www.demogracia.com
> --
On Monday, July 2, 2012 12:34:33 PM UTC+5, Álvaro G. Vicario wrote:
> El 02/07/2012 8:42, Fastian escribió/wrote:
>> <?
>> $image = file_get_contents('users.gif');
>>
>> header('Content-Type: image/gif');
>>
>> //imagegif($image); // I also tried to display image with imagegif but it also didnt work.
>
> The imagegif() function [1] expects «An image resource, returned by one
> of the image creation functions, such as imagecreatetruecolor()». I
> don't know how you reached the conclusion that you need such functions,
> given that are not even using PHP to generate the image :-?
>
> Probably, readfile() is all you need.
>
>
> [1] http://php.net/imagegif
> [1] http://php.net/readfile
>
>> But the image is NOT displayed on the browser.Where I am wrong?
>
> Browsers are basically designed to ignore invalid stuff and your
> "testing.php" script is possibly printing an error message rather than a
> valid GIF file. I suggest you remove the last layer and debug
> "testing.php" directly.
>
>
>
>
> --
> -- http://alvaro.es - Álvaro G. Vicario - Burgos, Spain
> -- Mi sitio sobre programación web: http://borrame.com
> -- Mi web de humor satinado: http://www.demogracia.com
> --
On Monday, July 2, 2012 12:34:33 PM UTC+5, Álvaro G. Vicario wrote:
> El 02/07/2012 8:42, Fastian escribió/wrote:
>> <?
>> $image = file_get_contents('users.gif');
>>
>> header('Content-Type: image/gif');
>>
>> //imagegif($image); // I also tried to display image with imagegif but it also didnt work.
>
> The imagegif() function [1] expects «An image resource, returned by one
> of the image creation functions, such as imagecreatetruecolor()». I
> don't know how you reached the conclusion that you need such functions,
> given that are not even using PHP to generate the image :-?
>
> Probably, readfile() is all you need.
>
>
> [1] http://php.net/imagegif
> [1] http://php.net/readfile
>
>> But the image is NOT displayed on the browser.Where I am wrong?
>
> Browsers are basically designed to ignore invalid stuff and your
> "testing.php" script is possibly printing an error message rather than a
> valid GIF file. I suggest you remove the last layer and debug
> "testing.php" directly.
>
>
>
>
> --
> -- http://alvaro.es - Álvaro G. Vicario - Burgos, Spain
> -- Mi sitio sobre programación web: http://borrame.com
> -- Mi web de humor satinado: http://www.demogracia.com
> --
I think readfile is useful when you know the name of the image so that you can access it with its name. In my case the I am trying to use file_get_contents function only because I am not aware of the name of the image file that will result from rendering. Have a look here: http://www.forkosh.com/mathtex.html OR view source of http://www.forkosh.com/mathtexpreview.html.
I thought that without knowing the name of the image you can still get the image output using file_get_contents function. Tell me if it possible to use readfile or with anyother function.
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