| Re: Undefined variable [message #181251 is a reply to message #181245] |
Thu, 25 April 2013 08:10   |
M. Strobel
Messages: 386
Registered: December 2011
Karma:
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Senior Member |
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Am 24.04.2013 15:51, schrieb Question Boy:
> On Apr 24, 6:20 am, Christoph Becker <cmbecke...@gmx.de> wrote:
>> Question Boy wrote:
>>> For instance, I have a block of code, such as:
>>
>>> if ($iBookedBy=="Other") {
>>> echo '<option selected value="Other">Other</option>';
>>> } else {
>>> echo '<option value="Other">Other</option>';
>>> }
>>
>>> which the log file reports as:
>>
>>> PHP Notice: Undefined variable: iBookedBy
>>
>> You should investigate, why $iBookeyBy is undefined. It is always
>> preferable to initialize a variable explicitely before you use it. This
>> is particularly important for PHP due to the dangerous register_globals
>> option (which was fortunately removed since PHP 5.4). If this is
>> enabled (what should never be), the code may be vulnerable. Checking
>> for isset($iBookeyBy) won't help in this case.
>>
>> --
>> Christoph M. Becker
>
> Thank you all for all the information! I have a lot of work ahead of
> me to clean thing up.
>
I propose a new reading of "PHP Notice: undefined variable...", it goes:
Hey, you are using a variable that is not defined. I will put a null into it.
Because I will make it easy for you.
If you don't care I won't either.
Maybe you expected the variable to contain something,
and your app logic will be screwed up.
It will be _a_lot_of_ work to find the error, but that's your problem.
/Str.
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