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sql how to have the total rows number in this case (this is correct question) [message #182513] Fri, 09 August 2013 14:32 Go to previous message
nawfer is currently offline  nawfer
Messages: 34
Registered: August 2011
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in this select
$query="SELECT *
FROM table1
ORDER BY
(CASE WHEN column2 = 100 THEN 1 ELSE 0 END + CASE WHEN column3='Y' THEN
2 ELSE 0 END) ASC, column1 ASC, column2 ASC;


how to have
a) the numeration for every row;
b) the total number of all the rows
c) the total number of column2 = 100 rows
d) the total number of column3='Y' rows


with the code I have that the rows are ordered and the rows with 100 and y
are sended at the end (first 100)

1
2
3
4
5
6
7
8
1 100
1 100
5 100
7 100
2 y
4 y
5 y


I know that exist the COUNT function, but so I must to executte the sql
more time;
I need execute sql only one time and can to have the rows number;
I thinked one solution can to be to fill a 4 column with the separated
numeration



I would like to have this

a 1
b 2
b 3
c 4
c 5
d 6
e 7
e 8
f 9
g 10
h 11
a 100 1
a 100 2
e 100 3
g 100 4
b y 1
d y 2
e y 3



or not know if whith the same sql can at the end created two column or
table so
total col 1 11
total col 2(the100) 4
total col 3(the y) 3
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