| foreach problem part two [message #184268] |
Thu, 19 December 2013 18:41  |
Mr Oldies
Messages: 241
Registered: October 2013
Karma: 0
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Senior Member |
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<?php
foreach ($aname as $item){
echo $aname[$item][1];
echo " (".$aname[$item][2].")";
}
?>
I decided to create a second array that holds only the artist and number of
records.
So why am I getting "invalid argument" with this?
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| Re: foreach problem part two [message #184275 is a reply to message #184270] |
Thu, 19 December 2013 19:20  |
The Natural Philosoph
Messages: 993
Registered: September 2010
Karma: 0
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Senior Member |
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On 19/12/13 19:00, Christoph Michael Becker wrote:
> Am 19.12.2013 19:41, schrieb richard:
>> <?php
>> foreach ($aname as $item){
>> echo $aname[$item][1];
>> echo " (".$aname[$item][2].")";
>> }
>> ?>
>>
>> I decided to create a second array that holds only the artist and number of
>> records.
>> So why am I getting "invalid argument" with this?
>
> You may consider reading the manual:
> <http://www.php.net/manual/en/control-structures.foreach.php>.
>
IF I had £5 for every time someone has suggested richard reads the
manaul THEN I'd be able to afford a new computer.
--
Ineptocracy
(in-ep-toc’-ra-cy) – a system of government where the least capable to
lead are elected by the least capable of producing, and where the
members of society least likely to sustain themselves or succeed, are
rewarded with goods and services paid for by the confiscated wealth of a
diminishing number of producers.
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| Re: foreach problem part two [message #184276 is a reply to message #184272] |
Thu, 19 December 2013 19:21 |
The Natural Philosoph
Messages: 993
Registered: September 2010
Karma: 0
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Senior Member |
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On 19/12/13 19:16, Denis McMahon wrote:
> On Thu, 19 Dec 2013 20:00:41 +0100, Christoph Michael Becker wrote:
>
>> You may consider reading the manual:
>> <http://www.php.net/manual/en/control-structures.foreach.php>.
>
> I suspect the reason richard doesn't read the manual is because it's full
> of big scary words like parameter, integer and boolean that he doesn't
> understand.
>
I am not convinced he can read at all.
--
Ineptocracy
(in-ep-toc’-ra-cy) – a system of government where the least capable to
lead are elected by the least capable of producing, and where the
members of society least likely to sustain themselves or succeed, are
rewarded with goods and services paid for by the confiscated wealth of a
diminishing number of producers.
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| fixed! (was: foreach problem part two) [message #184277 is a reply to message #184268] |
Thu, 19 December 2013 21:07 |
Mr Oldies
Messages: 241
Registered: October 2013
Karma: 0
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Senior Member |
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On Thu, 19 Dec 2013 13:41:51 -0500, richard wrote:
> <?php
> foreach ($aname as $item){
> echo $aname[$item][1];
> echo " (".$aname[$item][2].")";
> }
> ?>
>
> I decided to create a second array that holds only the artist and number of
> records.
> So why am I getting "invalid argument" with this?
<?php
$result=count($art60);
$acount=0;
while ($acount<=$result){
echo "<div class='blu'>";
$number=count($art60[$acount]);
echo $art60[$acount][0];
echo " (".$number.")";
echo "</div>";
$acount++;
}
?>
This version not only shows the names, but the number of songs each
produced as well.
http://mroldies.net/artists/60artists.php
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| Re: foreach problem part two [message #184278 is a reply to message #184268] |
Thu, 19 December 2013 22:34 |
Doug Miller
Messages: 171
Registered: August 2011
Karma: 0
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Senior Member |
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richard <noreply(at)example(dot)com> wrote in news:oib4w8z2sr5y$.15xxzxjds0xb0$.dlg@
40tude.net:
> <?php
> foreach ($aname as $item){
> echo $aname[$item][1];
> echo " (".$aname[$item][2].")";
> }
> ?>
>
> I decided to create a second array that holds only the artist and number of
> records.
> So why am I getting "invalid argument" with this?
Because you don't understand how foreach() works. RTFM.
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| Re: foreach problem part two [message #184279 is a reply to message #184278] |
Thu, 19 December 2013 23:39 |
Mr Oldies
Messages: 241
Registered: October 2013
Karma: 0
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Senior Member |
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On Thu, 19 Dec 2013 22:34:24 +0000 (UTC), Doug Miller wrote:
> richard <noreply(at)example(dot)com> wrote in news:oib4w8z2sr5y$.15xxzxjds0xb0$.dlg@
> 40tude.net:
>
>> <?php
>> foreach ($aname as $item){
>> echo $aname[$item][1];
>> echo " (".$aname[$item][2].")";
>> }
>> ?>
>>
>> I decided to create a second array that holds only the artist and number of
>> records.
>> So why am I getting "invalid argument" with this?
>
> Because you don't understand how foreach() works. RTFM.
I did.
There is a flaw in the works that is not discussed.
That being, it won't work with brackted arrays.
Works fine with standard arrays.
While (){}. however works and could care less which is used.
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| Re: foreach problem part two [message #184280 is a reply to message #184279] |
Fri, 20 December 2013 00:51 |
Jerry Stuckle
Messages: 2598
Registered: September 2010
Karma: 0
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Senior Member |
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On 12/19/2013 6:39 PM, richard wrote:
> On Thu, 19 Dec 2013 22:34:24 +0000 (UTC), Doug Miller wrote:
>
>> richard <noreply(at)example(dot)com> wrote in news:oib4w8z2sr5y$.15xxzxjds0xb0$.dlg@
>> 40tude.net:
>>
>>> <?php
>>> foreach ($aname as $item){
>>> echo $aname[$item][1];
>>> echo " (".$aname[$item][2].")";
>>> }
>>> ?>
>>>
>>> I decided to create a second array that holds only the artist and number of
>>> records.
>>> So why am I getting "invalid argument" with this?
>>
>> Because you don't understand how foreach() works. RTFM.
>
> I did.
> There is a flaw in the works that is not discussed.
> That being, it won't work with brackted arrays.
> Works fine with standard arrays.
>
> While (){}. however works and could care less which is used.
>
What do you mean by "bracketed arrays"? There is no such thing!
foreach() works fine with ANY array.
--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex(at)attglobal(dot)net
==================
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| Re: foreach problem part two [message #184281 is a reply to message #184279] |
Fri, 20 December 2013 01:09 |
Christoph Michael Bec
Messages: 207
Registered: June 2013
Karma: 0
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Senior Member |
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richard wrote:
> There is a flaw in the works that is not discussed.
> That being, it won't work with brackted arrays.
> Works fine with standard arrays.
Nonsense. PHP has only one array type.[1]
> While (){}. however works and could care less which is used.
Assume, you have an array:
$array = array('one', 'two', 'three');
Now you want to echo its elements in order. What is simpler and more
readable?
$i = 0;
while ($i < count($array)) {
echo $array[$i];
}
or
foreach ($array as $element) {
echo $element;
}
Additionally, the foreach loop is most likely faster.
[1] <http://www.php.net/manual/en/language.types.array.php>
--
Christoph M. Becker
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| Re: foreach problem part two [message #184283 is a reply to message #184279] |
Fri, 20 December 2013 03:11 |
Doug Miller
Messages: 171
Registered: August 2011
Karma: 0
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Senior Member |
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richard <noreply(at)example(dot)com> wrote in news:y1yigdragnyw$.c2kv48q50osj.dlg@
40tude.net:
> On Thu, 19 Dec 2013 22:34:24 +0000 (UTC), Doug Miller wrote:
>
>> richard <noreply(at)example(dot)com> wrote in news:oib4w8z2sr5y$.15xxzxjds0xb0$.dlg@
>> 40tude.net:
>>
>>> <?php
>>> foreach ($aname as $item){
>>> echo $aname[$item][1];
>>> echo " (".$aname[$item][2].")";
>>> }
>>> ?>
>>>
>>> I decided to create a second array that holds only the artist and number of
>>> records.
>>> So why am I getting "invalid argument" with this?
>>
>> Because you don't understand how foreach() works. RTFM.
>
> I did.
Then read it again, because you obviously didn't understand it first time through.
> There is a flaw in the works that is not discussed.
No, there isn't. The only flaw here is your failure to understand the way foreach() works.
RTFM.
> That being, it won't work with brackted arrays.
That's *not* where the problem is in your code. RTFM.
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| Re: foreach problem part two [message #184284 is a reply to message #184281] |
Fri, 20 December 2013 04:05 |
Mr Oldies
Messages: 241
Registered: October 2013
Karma: 0
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Senior Member |
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On Fri, 20 Dec 2013 02:09:46 +0100, Christoph Michael Becker wrote:
> richard wrote:
>
>> There is a flaw in the works that is not discussed.
>> That being, it won't work with brackted arrays.
>> Works fine with standard arrays.
>
> Nonsense. PHP has only one array type.[1]
>
>> While (){}. however works and could care less which is used.
>
> Assume, you have an array:
>
> $array = array('one', 'two', 'three');
>
> Now you want to echo its elements in order. What is simpler and more
> readable?
>
> $i = 0;
> while ($i < count($array)) {
> echo $array[$i];
> }
>
> or
>
> foreach ($array as $element) {
> echo $element;
> }
>
> Additionally, the foreach loop is most likely faster.
>
> [1] <http://www.php.net/manual/en/language.types.array.php>
As you and others so kindly keep repeating, RTFM!
$array[0][0]="data"
Is 100% valid!
In the arrays manual, it shows the use of bracketed arrays several times.
So why don't you tell them they are wrong?
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| Re: foreach problem part two [message #184285 is a reply to message #184284] |
Fri, 20 December 2013 04:37 |
Richard Damon
Messages: 58
Registered: August 2011
Karma: 0
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Member |
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On 12/19/13, 11:05 PM, richard wrote:
> On Fri, 20 Dec 2013 02:09:46 +0100, Christoph Michael Becker wrote:
>
>> richard wrote:
>>
>>> There is a flaw in the works that is not discussed.
>>> That being, it won't work with brackted arrays.
>>> Works fine with standard arrays.
>>
>> Nonsense. PHP has only one array type.[1]
>>
>>> While (){}. however works and could care less which is used.
>>
>> Assume, you have an array:
>>
>> $array = array('one', 'two', 'three');
>>
>> Now you want to echo its elements in order. What is simpler and more
>> readable?
>>
>> $i = 0;
>> while ($i < count($array)) {
>> echo $array[$i];
>> }
>>
>> or
>>
>> foreach ($array as $element) {
>> echo $element;
>> }
>>
>> Additionally, the foreach loop is most likely faster.
>>
>> [1] <http://www.php.net/manual/en/language.types.array.php>
>
> As you and others so kindly keep repeating, RTFM!
>
> $array[0][0]="data"
>
> Is 100% valid!
>
> In the arrays manual, it shows the use of bracketed arrays several times.
> So why don't you tell them they are wrong?
>
As far as I can tell, the PHP Manual NEVER calls this a "bracketed
array", and an array created this way is indistinguishable (after
creation) from the array created with the array() operator.
Creating a previously non-existent member by this member in a previously
created array does have some advantages.
I will also note, that you original program had no line like this (at
least that you showed us).
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| Re: foreach problem part two [message #184286 is a reply to message #184279] |
Fri, 20 December 2013 06:52 |
Arno Welzel
Messages: 317
Registered: October 2011
Karma: 0
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Senior Member |
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richard, 2013-12-20 00:39:
> On Thu, 19 Dec 2013 22:34:24 +0000 (UTC), Doug Miller wrote:
>
>> richard <noreply(at)example(dot)com> wrote in news:oib4w8z2sr5y$.15xxzxjds0xb0$.dlg@
>> 40tude.net:
>>
>>> <?php
>>> foreach ($aname as $item){
>>> echo $aname[$item][1];
>>> echo " (".$aname[$item][2].")";
>>> }
>>> ?>
>>>
>>> I decided to create a second array that holds only the artist and number of
>>> records.
>>> So why am I getting "invalid argument" with this?
>>
>> Because you don't understand how foreach() works. RTFM.
>
> I did.
> There is a flaw in the works that is not discussed.
> That being, it won't work with brackted arrays.
> Works fine with standard arrays.
Sigh...
There is no thing like "bracketed arrays" or "standard arrays". This is
called one-dimensional and multi-dimensional. And of course foreach()
works fine with every kind of array.
<?php
$myarray = array(
array( 'Apple', 1 ),
array( 'Pie', 2 )
);
foreach($myarray as $item)
{
echo $item[0] . ' - ' . $item[1] . '<br />';
}
?>
You just don't understand it - as usual.
> While (){}. however works and could care less which is used.
As usual. while() needs more code, is slower and is prone to errors.
Really - software development is not your thing. It seems you are
mentally not capable of understanding the principles.
--
Arno Welzel
http://arnowelzel.de
http://de-rec-fahrrad.de
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| Re: foreach problem part two [message #184291 is a reply to message #184284] |
Fri, 20 December 2013 12:11 |
Norman Peelman
Messages: 126
Registered: September 2010
Karma: 0
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Senior Member |
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On 12/19/2013 11:05 PM, richard wrote:
> On Fri, 20 Dec 2013 02:09:46 +0100, Christoph Michael Becker wrote:
>
>> richard wrote:
>>
>>> There is a flaw in the works that is not discussed.
>>> That being, it won't work with brackted arrays.
>>> Works fine with standard arrays.
>>
>> Nonsense. PHP has only one array type.[1]
>>
>>> While (){}. however works and could care less which is used.
>>
>> Assume, you have an array:
>>
>> $array = array('one', 'two', 'three');
>>
>> Now you want to echo its elements in order. What is simpler and more
>> readable?
>>
>> $i = 0;
>> while ($i < count($array)) {
>> echo $array[$i];
>> }
>>
>> or
>>
>> foreach ($array as $element) {
>> echo $element;
>> }
>>
>> Additionally, the foreach loop is most likely faster.
>>
>> [1] <http://www.php.net/manual/en/language.types.array.php>
>
> As you and others so kindly keep repeating, RTFM!
>
> $array[0][0]="data"
>
> Is 100% valid!
>
> In the arrays manual, it shows the use of bracketed arrays several times.
> So why don't you tell them they are wrong?
>
Then maybe you should read it again, specifically "Creating/modifying
with square bracket syntax". That tells you why it isn't working.
However:
$year = "60";
$alist = "art".$year;
$$alist = array(0 => array(0 => "00", 1 => "01"), 1 => array(0 => "10",
1 => "11"));
....is a small example of what you are trying to do.
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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| Re: foreach problem part two [message #184292 is a reply to message #184285] |
Fri, 20 December 2013 12:14 |
Norman Peelman
Messages: 126
Registered: September 2010
Karma: 0
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Senior Member |
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On 12/19/2013 11:37 PM, Richard Damon wrote:
> On 12/19/13, 11:05 PM, richard wrote:
>> On Fri, 20 Dec 2013 02:09:46 +0100, Christoph Michael Becker wrote:
>>
>>> richard wrote:
>>>
>>>> There is a flaw in the works that is not discussed.
>>>> That being, it won't work with brackted arrays.
>>>> Works fine with standard arrays.
>>>
>>> Nonsense. PHP has only one array type.[1]
>>>
>>>> While (){}. however works and could care less which is used.
>>>
>>> Assume, you have an array:
>>>
>>> $array = array('one', 'two', 'three');
>>>
>>> Now you want to echo its elements in order. What is simpler and more
>>> readable?
>>>
>>> $i = 0;
>>> while ($i < count($array)) {
>>> echo $array[$i];
>>> }
>>>
>>> or
>>>
>>> foreach ($array as $element) {
>>> echo $element;
>>> }
>>>
>>> Additionally, the foreach loop is most likely faster.
>>>
>>> [1] <http://www.php.net/manual/en/language.types.array.php>
>>
>> As you and others so kindly keep repeating, RTFM!
>>
>> $array[0][0]="data"
>>
>> Is 100% valid!
>>
>> In the arrays manual, it shows the use of bracketed arrays several times.
>> So why don't you tell them they are wrong?
>>
>
> As far as I can tell, the PHP Manual NEVER calls this a "bracketed
> array", and an array created this way is indistinguishable (after
> creation) from the array created with the array() operator.
>
> Creating a previously non-existent member by this member in a previously
> created array does have some advantages.
>
> I will also note, that you original program had no line like this (at
> least that you showed us).
>
This is not 100% legal syntax because the second [0] acts as a string
offset instead of an index:
$alist[0][0] = "data";
Fatal error: Cannot use string offset as an array... you must use
*array()* to set these up.
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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| Re: foreach problem part two [message #184293 is a reply to message #184284] |
Fri, 20 December 2013 13:17 |
Doug Miller
Messages: 171
Registered: August 2011
Karma: 0
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Senior Member |
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richard <noreply(at)example(dot)com> wrote in news:t6ds31so68b7.1s80a7lxre6po$.dlg@
40tude.net:
> $array[0][0]="data"
>
> Is 100% valid!
>
> In the arrays manual, it shows the use of bracketed arrays several times.
> So why don't you tell them they are wrong?
The problem isn't your array notation, the problem is your misunderstanding of how foreach()
works. RTFM.
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| Re: foreach problem part two [message #184295 is a reply to message #184292] |
Fri, 20 December 2013 15:35 |
Thomas 'PointedEars'
Messages: 701
Registered: October 2010
Karma: 0
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Senior Member |
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Norman Peelman wrote:
> This is not 100% legal syntax because the second [0] acts as a string
> offset instead of an index:
>
> $alist[0][0] = "data";
> Fatal error: Cannot use string offset as an array... you must use
> *array()* to set these up.
Unsurprisingly, utter nonsense from you again.
$ php -r '$a[0] = 42; var_dump($a["0"]);'
int(42)
In fact,
$alist[0][0] = "data";
is equivalent to
$alist = array(array("data"));
or
$alist = array(0 => array("data"));
or
$alist = array(array(0 => "data"));
or
$alist = array(0 => array(0 => "data"));
or variations of that where the key is the string '0' or "0", if $alist did
not exist before.
It is equivalent to
$alist[0] = array("data");
and variations of that, including those where the keys are '0', if $alist
existed before but did not have an element with key 0.
And it is equivalent to itself if $alist[0] referred to an array before
(i.e., it modifies the element with index 0 of the array that is the element
with index 0 of the outer array).
That you can create „multi-dimensional“ arrays, which can even be
associative, with just one line, is the beauty of PHP.
PointedEars
--
realism: HTML 4.01 Strict
evangelism: XHTML 1.0 Strict
madness: XHTML 1.1 as application/xhtml+xml
-- Bjoern Hoehrmann
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| Re: foreach problem part two [message #184296 is a reply to message #184284] |
Fri, 20 December 2013 17:14 |
Evan Platt
Messages: 124
Registered: November 2010
Karma: 0
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Senior Member |
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On Thu, 19 Dec 2013 23:05:59 -0500, richard <noreply(at)example(dot)com>
wrote:
> As you and others so kindly keep repeating, RTFM!
>
> $array[0][0]="data"
>
> Is 100% valid!
>
> In the arrays manual, it shows the use of bracketed arrays several times.
> So why don't you tell them they are wrong?
Why don't you submit it as a bug if you're so confident you're right,
bullis?
Then show us the bug link.
Please.
This should be good.
--
To reply via e-mail, remove The Obvious and .invalid from my e-mail address.
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| Re: foreach problem part two [message #184298 is a reply to message #184279] |
Fri, 20 December 2013 18:37 |
Denis McMahon
Messages: 634
Registered: September 2010
Karma: 0
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Senior Member |
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On Thu, 19 Dec 2013 18:39:28 -0500, richard wrote:
> On Thu, 19 Dec 2013 22:34:24 +0000 (UTC), Doug Miller wrote:
>
>> richard <noreply(at)example(dot)com> wrote in
>> news:oib4w8z2sr5y$.15xxzxjds0xb0$.dlg@
>> 40tude.net:
>>
>>> <?php
>>> foreach ($aname as $item){
>>> echo $aname[$item][1];
>>> echo " (".$aname[$item][2].")";
>>> }
>>> ?>
>>>
>>> I decided to create a second array that holds only the artist and
>>> number of records.
>>> So why am I getting "invalid argument" with this?
>>
>> Because you don't understand how foreach() works. RTFM.
>
> I did.
> There is a flaw in the works that is not discussed.
> That being, it won't work with brackted arrays.
> Works fine with standard arrays.
Foreach works with all arrays. At the foreach level, all arrays are one-
dimensional, in that foreach works with the topmost dimension of the
array being processed.
The only flaw is your lack of understanding of how foreach works.
If you read and comprehended the manual entry for foreach, you would
realise this.
--
Denis McMahon, denismfmcmahon(at)gmail(dot)com
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| Re: foreach problem part two [message #184300 is a reply to message #184284] |
Fri, 20 December 2013 18:52 |
Denis McMahon
Messages: 634
Registered: September 2010
Karma: 0
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Senior Member |
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On Thu, 19 Dec 2013 23:05:59 -0500, richard wrote:
> On Fri, 20 Dec 2013 02:09:46 +0100, Christoph Michael Becker wrote:
>
>> richard wrote:
>>
>>> There is a flaw in the works that is not discussed.
>>> That being, it won't work with brackted arrays.
>>> Works fine with standard arrays.
>>
>> Nonsense. PHP has only one array type.[1]
> As you and others so kindly keep repeating, RTFM!
>
> $array[0][0]="data"
>
> Is 100% valid!
Yes, it's an array of arrays. But it's still just an array of things,
even if each thing is an array.
PHP has a single array type. An array is a collection of things. The
things can be arrays, ints, strings, classes, etc, but the containing
array is just an array of things.
--
Denis McMahon, denismfmcmahon(at)gmail(dot)com
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| Re: foreach problem part two [message #184536 is a reply to message #184281] |
Tue, 07 January 2014 04:13 |
John Smith
Messages: 7
Registered: January 2014
Karma: 0
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Junior Member |
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On Fri, 20 Dec 2013 02:09:46 +0100, Christoph Michael Becker
<cmbecker69(at)arcor(dot)de> wrote:
> richard wrote:
>
>> There is a flaw in the works that is not discussed.
>> That being, it won't work with brackted arrays.
>> Works fine with standard arrays.
>
> Nonsense. PHP has only one array type.[1]
>
>> While (){}. however works and could care less which is used.
>
> Assume, you have an array:
>
> $array = array('one', 'two', 'three');
>
> Now you want to echo its elements in order. What is simpler and more
> readable?
>
> $i = 0;
> while ($i < count($array)) {
> echo $array[$i];
> }
>
> or
>
> foreach ($array as $element) {
> echo $element;
> }
>
> Additionally, the foreach loop is most likely faster.
>
> [1] <http://www.php.net/manual/en/language.types.array.php>
At the first example you don't have to increment the $i?
John
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| Re: foreach problem part two [message #184538 is a reply to message #184536] |
Tue, 07 January 2014 09:07 |
Christoph Michael Bec
Messages: 207
Registered: June 2013
Karma: 0
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Senior Member |
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John Smith wrote:
> On Fri, 20 Dec 2013 02:09:46 +0100, Christoph Michael Becker
> <cmbecker69(at)arcor(dot)de> wrote:
>
>> Assume, you have an array:
>>
>> $array = array('one', 'two', 'three');
>>
>> Now you want to echo its elements in order. What is simpler and more
>> readable?
>>
>> $i = 0;
>> while ($i < count($array)) {
>> echo $array[$i];
>> }
>
> At the first example you don't have to increment the $i?
Oops! Of course you'd have to:
$i = 0;
while ($i < count($array)) {
echo $array[$i];
$i++;
}
--
Christoph M. Becker
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