| Re: foreach problem part two [message #184279 is a reply to message #184278] |
Thu, 19 December 2013 23:39   |
Mr Oldies
Messages: 241
Registered: October 2013
Karma:
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Senior Member |
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On Thu, 19 Dec 2013 22:34:24 +0000 (UTC), Doug Miller wrote:
> richard <noreply(at)example(dot)com> wrote in news:oib4w8z2sr5y$.15xxzxjds0xb0$.dlg@
> 40tude.net:
>
>> <?php
>> foreach ($aname as $item){
>> echo $aname[$item][1];
>> echo " (".$aname[$item][2].")";
>> }
>> ?>
>>
>> I decided to create a second array that holds only the artist and number of
>> records.
>> So why am I getting "invalid argument" with this?
>
> Because you don't understand how foreach() works. RTFM.
I did.
There is a flaw in the works that is not discussed.
That being, it won't work with brackted arrays.
Works fine with standard arrays.
While (){}. however works and could care less which is used.
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