| Re: foreach problem part two [message #184292 is a reply to message #184285] |
Fri, 20 December 2013 12:14   |
Norman Peelman
Messages: 126
Registered: September 2010
Karma:
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Senior Member |
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On 12/19/2013 11:37 PM, Richard Damon wrote:
> On 12/19/13, 11:05 PM, richard wrote:
>> On Fri, 20 Dec 2013 02:09:46 +0100, Christoph Michael Becker wrote:
>>
>>> richard wrote:
>>>
>>>> There is a flaw in the works that is not discussed.
>>>> That being, it won't work with brackted arrays.
>>>> Works fine with standard arrays.
>>>
>>> Nonsense. PHP has only one array type.[1]
>>>
>>>> While (){}. however works and could care less which is used.
>>>
>>> Assume, you have an array:
>>>
>>> $array = array('one', 'two', 'three');
>>>
>>> Now you want to echo its elements in order. What is simpler and more
>>> readable?
>>>
>>> $i = 0;
>>> while ($i < count($array)) {
>>> echo $array[$i];
>>> }
>>>
>>> or
>>>
>>> foreach ($array as $element) {
>>> echo $element;
>>> }
>>>
>>> Additionally, the foreach loop is most likely faster.
>>>
>>> [1] <http://www.php.net/manual/en/language.types.array.php>
>>
>> As you and others so kindly keep repeating, RTFM!
>>
>> $array[0][0]="data"
>>
>> Is 100% valid!
>>
>> In the arrays manual, it shows the use of bracketed arrays several times.
>> So why don't you tell them they are wrong?
>>
>
> As far as I can tell, the PHP Manual NEVER calls this a "bracketed
> array", and an array created this way is indistinguishable (after
> creation) from the array created with the array() operator.
>
> Creating a previously non-existent member by this member in a previously
> created array does have some advantages.
>
> I will also note, that you original program had no line like this (at
> least that you showed us).
>
This is not 100% legal syntax because the second [0] acts as a string
offset instead of an index:
$alist[0][0] = "data";
Fatal error: Cannot use string offset as an array... you must use
*array()* to set these up.
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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