Filling an array with random input doesn't quite work [message #185211] |
Wed, 12 March 2014 17:18 |
Mr Oldies
Messages: 241 Registered: October 2013
Karma: 0
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Senior Member |
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$x=1;
while ($x<40){
$yr=range(60,69);
shuffle($yr);
$ayr[$x]=$yr[$x];
echo $ayr[$x]."<br>";
$x++;
}
I am attempting to load an array based upon the range of numbers 60 through
69.
The array will have 40 items.
This code produces 9 items just fine.
The rest of the array is empty.
What am I missing?
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Re: Filling an array with random input doesn't quite work [message #185212 is a reply to message #185211] |
Wed, 12 March 2014 17:36 |
Tim Streater
Messages: 328 Registered: September 2010
Karma: 0
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Senior Member |
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In article <12lin35i3xsev(dot)abk024ld5l8l(dot)dlg(at)40tude(dot)net>, richard
<noreply(at)example(dot)com> wrote:
> $x=1;
> while ($x<40){
> $yr=range(60,69);
> shuffle($yr);
> $ayr[$x]=$yr[$x];
> echo $ayr[$x]."<br>";
> $x++;
> }
>
>
> I am attempting to load an array based upon the range of numbers 60 through
> 69.
> The array will have 40 items.
> This code produces 9 items just fine.
> The rest of the array is empty.
> What am I missing?
This:
$ayr[$x]=$yr[$x];
isn't gonna work once $x gets above 9, now is it? Your array $yr only
contains 10 items.
--
"I am enclosing two tickets to the first night of my new play; bring a
friend.... if you have one." - GB Shaw to Churchill "Cannot possibly
attend first night, will attend second... if there is one." - Winston
Churchill, in response.
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Re: Filling an array with random input doesn't quite work [message #185213 is a reply to message #185211] |
Wed, 12 March 2014 19:02 |
Doug Miller
Messages: 171 Registered: August 2011
Karma: 0
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Senior Member |
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richard <noreply(at)example(dot)com> wrote in news:12lin35i3xsev.abk024ld5l8l.dlg@
40tude.net:
> $x=1;
> while ($x<40){
> $yr=range(60,69);
> shuffle($yr);
> $ayr[$x]=$yr[$x];
> echo $ayr[$x]."<br>";
> $x++;
> }
>
>
> I am attempting to load an array based upon the range of numbers 60 through
> 69.
> The array will have 40 items.
> This code produces 9 items just fine.
> The rest of the array is empty.
> What am I missing?
This line:
$ayr[$x]=$yr[$x];
What is the "value" of $yr[$x] when x is greater than 9?
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Re: Filling an array with random input doesn't quite work [message #185215 is a reply to message #185211] |
Wed, 12 March 2014 20:34 |
Denis McMahon
Messages: 634 Registered: September 2010
Karma: 0
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Senior Member |
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On Wed, 12 Mar 2014 13:18:19 -0400, richard wrote:
> $x=1;
> while ($x<40){
> $yr=range(60,69); shuffle($yr); $ayr[$x]=$yr[$x]; echo
> $ayr[$x]."<br>";
> $x++;
> }
>
>
> I am attempting to load an array based upon the range of numbers 60
> through 69.
> The array will have 40 items.
> This code produces 9 items just fine.
> The rest of the array is empty.
> What am I missing?
You're missing a richardian fuck up in the array indexing!
You also seem to be ignoring a message something like:
"PHP Notice: Undefined offset: 38 in /richardian_array_fuckup.php on
line 13"
Try:
$x=1;
while ($x<40){
$yr=range(60,69);
shuffle($yr);
$n = count($yr);
echo "\$x is {$x}, size of \$yr is {$n} elements, \$yr[\$x] is '{$yr
[$x]}'<br>\n";
$ayr[$x]=$yr[$x];
echo $ayr[$x]."<br>\n";
$x++;
}
and see if that helps you work it out.
By the way, the following code might be useful:
$a=40;
$b=array();
$c=range(60,69);
while(--$a)$b[$a]=$c[array_rand($c)];
assuming that what you actually want is an array of 39 elements indexed
1..39 with random values from 60 to 69.
I doubt that's exactly what you do want, but that's my best guess at what
your code is intended to create.
--
Denis McMahon, denismfmcmahon(at)gmail(dot)com
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Re: solved! Re: Filling an array with random input doesn't quite work [message #185220 is a reply to message #185217] |
Thu, 13 March 2014 01:14 |
Mr Oldies
Messages: 241 Registered: October 2013
Karma: 0
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Senior Member |
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On Wed, 12 Mar 2014 22:49:38 +0000, Tim Streater wrote:
> In article <85dkidwa0h67(dot)ecj3ezgrqtzk$(dot)dlg(at)40tude(dot)net>, richard
> <noreply(at)example(dot)com> wrote:
>
> You're welcome.
>
>> $x=1;
>> while ($x<40){
>> $yr=rand(1,10);
>> $yr=$yr+59;
>>
>> $num=rand(1,100);
>> if ($num<100){$num="0".$num;}
>> if ($num<10){$num="0".$num;}
>
> What is the point if this second "if"? You've already covered that with
> the first.
>
I do it this way because I've been doing the same method in BASIC for
years. It works fine.
It also helps for sorting purposes.
by having all the strings the same length helps to guarantee that sorting
will not screw it up.
When the number equals 1,
the first "if" adds a zero.
The second "if" adds another zero because it is less than 10.
numbers between 10 and 100 only get one zero added.
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Re: solved! Re: Filling an array with random input doesn't quite work [message #185221 is a reply to message #185219] |
Thu, 13 March 2014 02:43 |
Mr Oldies
Messages: 241 Registered: October 2013
Karma: 0
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Senior Member |
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On Thu, 13 Mar 2014 01:11:59 +0100, Christoph Michael Becker wrote:
> Tim Streater wrote:
>
>> In article <85dkidwa0h67(dot)ecj3ezgrqtzk$(dot)dlg(at)40tude(dot)net>, richard
>> <noreply(at)example(dot)com> wrote:
>>
>> You're welcome.
>>
>>> $x=1;
>>> while ($x<40){
>>> $yr=rand(1,10);
>>> $yr=$yr+59;
>>> $num=rand(1,100);
>>> if ($num<100){$num="0".$num;}
>>> if ($num<10){$num="0".$num;}
>>
>> What is the point if this second "if"? You've already covered that with
>> the first.
>
> That serves to add padding to three characters. The last three lines
> could be replaced with the following:
>
> str_pad(rand(1, 100), 3, '0', STR_PAD_LEFT);
>
>>>
>>> $song[$x]="http://mroldies.net/audio/19$yr/".$yr."-".$num.".mp3";
>>> $x++;
>>> }
thanks for the clue. I may use it.
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Re: Filling an array with random input doesn't quite work [message #185225 is a reply to message #185211] |
Thu, 13 March 2014 03:02 |
Norman Peelman
Messages: 126 Registered: September 2010
Karma: 0
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Senior Member |
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On 03/12/2014 01:18 PM, richard wrote:
> $x=1;
> while ($x<40){
> $yr=range(60,69);
> shuffle($yr);
> $ayr[$x]=$yr[$x];
> echo $ayr[$x]."<br>";
> $x++;
> }
>
>
> I am attempting to load an array based upon the range of numbers 60 through
> 69.
> The array will have 40 items.
> This code produces 9 items just fine.
> The rest of the array is empty.
> What am I missing?
>
for ($items=1; $items<=40; $items++)
{
$ayr[$items] = range(60,69);
shuffle(&$ayr[$items]);
}
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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Re: Filling an array with random input doesn't quite work [message #185226 is a reply to message #185225] |
Thu, 13 March 2014 03:11 |
Jerry Stuckle
Messages: 2598 Registered: September 2010
Karma: 0
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Senior Member |
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On 3/12/2014 11:02 PM, Norman Peelman wrote:
> On 03/12/2014 01:18 PM, richard wrote:
>> $x=1;
>> while ($x<40){
>> $yr=range(60,69);
>> shuffle($yr);
>> $ayr[$x]=$yr[$x];
>> echo $ayr[$x]."<br>";
>> $x++;
>> }
>>
>>
>> I am attempting to load an array based upon the range of numbers 60
>> through
>> 69.
>> The array will have 40 items.
>> This code produces 9 items just fine.
>> The rest of the array is empty.
>> What am I missing?
>>
>
> for ($items=1; $items<=40; $items++)
> {
> $ayr[$items] = range(60,69);
> shuffle(&$ayr[$items]);
> }
>
>
Why would you shuffle a single item?
--
==================
Remove the "x" from my email address
Jerry Stuckle
jstucklex(at)attglobal(dot)net
==================
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Re: Filling an array with random input doesn't quite work [message #185229 is a reply to message #185225] |
Thu, 13 March 2014 04:31 |
Norman Peelman
Messages: 126 Registered: September 2010
Karma: 0
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Senior Member |
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On 03/12/2014 11:02 PM, Norman Peelman wrote:
> On 03/12/2014 01:18 PM, richard wrote:
>> $x=1;
>> while ($x<40){
>> $yr=range(60,69);
>> shuffle($yr);
>> $ayr[$x]=$yr[$x];
>> echo $ayr[$x]."<br>";
>> $x++;
>> }
>>
>>
>> I am attempting to load an array based upon the range of numbers 60
>> through
>> 69.
>> The array will have 40 items.
>> This code produces 9 items just fine.
>> The rest of the array is empty.
>> What am I missing?
>>
>
> for ($items=1; $items<=40; $items++)
> {
> $ayr[$items] = range(60,69);
> shuffle(&$ayr[$items]);
> }
>
>
$yr = range(60,69);
for ($items=1; $items<=40; $items++)
{
$ayr[$items] = $yr;
shuffle(&$ayr[$items]);
}
or
$yr = range(60,69);
for ($items=1; $items<=40; $items++)
{
shuffle(&$yr);
$ayr[$items] = $yr;
}
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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Re: solved! Re: Filling an array with random input doesn't quite work (was: Filling an array with random input doesn't quite work) [message #185232 is a reply to message #185217] |
Thu, 13 March 2014 16:23 |
Denis McMahon
Messages: 634 Registered: September 2010
Karma: 0
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Senior Member |
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On Wed, 12 Mar 2014 22:49:38 +0000, Tim Streater wrote:
> Ricjard Teh Stoopid tried to code something, and this is what escaped
to the internet:
>> $num=rand(1,100);
>> if ($num<100){$num="0".$num;}
>> if ($num<10){$num="0".$num;}
> What is the point if this second "if"? You've already covered that with
> the first.
I think what he means to do is:
$x=40;
$song=array();
while(--$x)$song[$x]=sprintf("http://mroldies.net/audio/19%2d/%2d-%
03d.mp3",$yr=rand(60,69),$yr,rand(1,100));
--
Denis McMahon, denismfmcmahon(at)gmail(dot)com
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Re: Filling an array with random input doesn't quite work [message #185241 is a reply to message #185226] |
Fri, 14 March 2014 13:31 |
Norman Peelman
Messages: 126 Registered: September 2010
Karma: 0
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Senior Member |
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On 03/12/2014 11:11 PM, Jerry Stuckle wrote:
> On 3/12/2014 11:02 PM, Norman Peelman wrote:
>> On 03/12/2014 01:18 PM, richard wrote:
>>> $x=1;
>>> while ($x<40){
>>> $yr=range(60,69);
>>> shuffle($yr);
>>> $ayr[$x]=$yr[$x];
>>> echo $ayr[$x]."<br>";
>>> $x++;
>>> }
>>>
>>>
>>> I am attempting to load an array based upon the range of numbers 60
>>> through
>>> 69.
>>> The array will have 40 items.
>>> This code produces 9 items just fine.
>>> The rest of the array is empty.
>>> What am I missing?
>>>
>>
>> for ($items=1; $items<=40; $items++)
>> {
>> $ayr[$items] = range(60,69);
>> shuffle(&$ayr[$items]);
>> }
>>
>>
>
> Why would you shuffle a single item?
>
>
$ayr[$items] is an Array
php > print_r($ayr);
Array
(
[1] => Array
(
[0] => 60
[1] => 61
[2] => 62
[3] => 63
[4] => 64
[5] => 65
[6] => 66
[7] => 67
[8] => 68
[9] => 69
)
)
.... after Shuffle:
php > shuffle(&$ayr[1]);
php > print_r($ayr[1]);
Array
(
[0] => 67
[1] => 69
[2] => 66
[3] => 61
[4] => 62
[5] => 60
[6] => 64
[7] => 68
[8] => 63
[9] => 65
)
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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Re: Filling an array with random input doesn't quite work [message #185242 is a reply to message #185241] |
Fri, 14 March 2014 15:00 |
Jerry Stuckle
Messages: 2598 Registered: September 2010
Karma: 0
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Senior Member |
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On 3/14/2014 9:31 AM, Norman Peelman wrote:
> On 03/12/2014 11:11 PM, Jerry Stuckle wrote:
>> On 3/12/2014 11:02 PM, Norman Peelman wrote:
>>> On 03/12/2014 01:18 PM, richard wrote:
>>>> $x=1;
>>>> while ($x<40){
>>>> $yr=range(60,69);
>>>> shuffle($yr);
>>>> $ayr[$x]=$yr[$x];
>>>> echo $ayr[$x]."<br>";
>>>> $x++;
>>>> }
>>>>
>>>>
>>>> I am attempting to load an array based upon the range of numbers 60
>>>> through
>>>> 69.
>>>> The array will have 40 items.
>>>> This code produces 9 items just fine.
>>>> The rest of the array is empty.
>>>> What am I missing?
>>>>
>>>
>>> for ($items=1; $items<=40; $items++)
>>> {
>>> $ayr[$items] = range(60,69);
>>> shuffle(&$ayr[$items]);
>>> }
>>>
>>>
>>
>> Why would you shuffle a single item?
>>
>>
>
> $ayr[$items] is an Array
>
> php > print_r($ayr);
> Array
> (
> [1] => Array
> (
> [0] => 60
> [1] => 61
> [2] => 62
> [3] => 63
> [4] => 64
> [5] => 65
> [6] => 66
> [7] => 67
> [8] => 68
> [9] => 69
> )
>
> )
>
> ... after Shuffle:
>
> php > shuffle(&$ayr[1]);
> php > print_r($ayr[1]);
> Array
> (
> [0] => 67
> [1] => 69
> [2] => 66
> [3] => 61
> [4] => 62
> [5] => 60
> [6] => 64
> [7] => 68
> [8] => 63
> [9] => 65
> )
>
>
>
Sorry, I was in a hurry and wasn't paying as much attention.
But then why have 40 different arrays of 10 items each, anyway?
--
==================
Remove the "x" from my email address
Jerry Stuckle
jstucklex(at)attglobal(dot)net
==================
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Re: Filling an array with random input doesn't quite work [message #185243 is a reply to message #185242] |
Fri, 14 March 2014 15:47 |
Norman Peelman
Messages: 126 Registered: September 2010
Karma: 0
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Senior Member |
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On 03/14/2014 11:00 AM, Jerry Stuckle wrote:
> On 3/14/2014 9:31 AM, Norman Peelman wrote:
>> On 03/12/2014 11:11 PM, Jerry Stuckle wrote:
>>> On 3/12/2014 11:02 PM, Norman Peelman wrote:
>>>> On 03/12/2014 01:18 PM, richard wrote:
>>>> > $x=1;
>>>> > while ($x<40){
>>>> > $yr=range(60,69);
>>>> > shuffle($yr);
>>>> > $ayr[$x]=$yr[$x];
>>>> > echo $ayr[$x]."<br>";
>>>> > $x++;
>>>> > }
>>>> >
>>>> >
>>>> > I am attempting to load an array based upon the range of numbers 60
>>>> > through
>>>> > 69.
>>>> > The array will have 40 items.
>>>> > This code produces 9 items just fine.
>>>> > The rest of the array is empty.
>>>> > What am I missing?
>>>> >
>>>>
>>>> for ($items=1; $items<=40; $items++)
>>>> {
>>>> $ayr[$items] = range(60,69);
>>>> shuffle(&$ayr[$items]);
>>>> }
>>>>
>>>>
>>>
>>> Why would you shuffle a single item?
>>>
>>>
>>
>> $ayr[$items] is an Array
>>
>> php > print_r($ayr);
>> Array
>> (
>> [1] => Array
>> (
>> [0] => 60
>> [1] => 61
>> [2] => 62
>> [3] => 63
>> [4] => 64
>> [5] => 65
>> [6] => 66
>> [7] => 67
>> [8] => 68
>> [9] => 69
>> )
>>
>> )
>>
>> ... after Shuffle:
>>
>> php > shuffle(&$ayr[1]);
>> php > print_r($ayr[1]);
>> Array
>> (
>> [0] => 67
>> [1] => 69
>> [2] => 66
>> [3] => 61
>> [4] => 62
>> [5] => 60
>> [6] => 64
>> [7] => 68
>> [8] => 63
>> [9] => 65
>> )
>>
>>
>>
>
> Sorry, I was in a hurry and wasn't paying as much attention.
>
> But then why have 40 different arrays of 10 items each, anyway?
>
I don't even know why there are 40 items when you are pulling from a
selection of 10 - there's going to be duplicates. Maybe that doesn't
matter... I think someone else actually had what Richard was really after.
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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Re: Filling an array with random input doesn't quite work [message #185244 is a reply to message #185243] |
Fri, 14 March 2014 16:55 |
Jerry Stuckle
Messages: 2598 Registered: September 2010
Karma: 0
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Senior Member |
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On 3/14/2014 11:47 AM, Norman Peelman wrote:
> On 03/14/2014 11:00 AM, Jerry Stuckle wrote:
>> On 3/14/2014 9:31 AM, Norman Peelman wrote:
>>> On 03/12/2014 11:11 PM, Jerry Stuckle wrote:
>>>> On 3/12/2014 11:02 PM, Norman Peelman wrote:
>>>> > On 03/12/2014 01:18 PM, richard wrote:
>>>> >> $x=1;
>>>> >> while ($x<40){
>>>> >> $yr=range(60,69);
>>>> >> shuffle($yr);
>>>> >> $ayr[$x]=$yr[$x];
>>>> >> echo $ayr[$x]."<br>";
>>>> >> $x++;
>>>> >> }
>>>> >>
>>>> >>
>>>> >> I am attempting to load an array based upon the range of numbers 60
>>>> >> through
>>>> >> 69.
>>>> >> The array will have 40 items.
>>>> >> This code produces 9 items just fine.
>>>> >> The rest of the array is empty.
>>>> >> What am I missing?
>>>> >>
>>>> >
>>>> > for ($items=1; $items<=40; $items++)
>>>> > {
>>>> > $ayr[$items] = range(60,69);
>>>> > shuffle(&$ayr[$items]);
>>>> > }
>>>> >
>>>> >
>>>>
>>>> Why would you shuffle a single item?
>>>>
>>>>
>>>
>>> $ayr[$items] is an Array
>>>
>>> php > print_r($ayr);
>>> Array
>>> (
>>> [1] => Array
>>> (
>>> [0] => 60
>>> [1] => 61
>>> [2] => 62
>>> [3] => 63
>>> [4] => 64
>>> [5] => 65
>>> [6] => 66
>>> [7] => 67
>>> [8] => 68
>>> [9] => 69
>>> )
>>>
>>> )
>>>
>>> ... after Shuffle:
>>>
>>> php > shuffle(&$ayr[1]);
>>> php > print_r($ayr[1]);
>>> Array
>>> (
>>> [0] => 67
>>> [1] => 69
>>> [2] => 66
>>> [3] => 61
>>> [4] => 62
>>> [5] => 60
>>> [6] => 64
>>> [7] => 68
>>> [8] => 63
>>> [9] => 65
>>> )
>>>
>>>
>>>
>>
>> Sorry, I was in a hurry and wasn't paying as much attention.
>>
>> But then why have 40 different arrays of 10 items each, anyway?
>>
>
> I don't even know why there are 40 items when you are pulling from a
> selection of 10 - there's going to be duplicates. Maybe that doesn't
> matter... I think someone else actually had what Richard was really after.
>
>
>
But each item in your list is an array. He wants single values.
--
==================
Remove the "x" from my email address
Jerry Stuckle
jstucklex(at)attglobal(dot)net
==================
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Re: Filling an array with random input doesn't quite work [message #185250 is a reply to message #185211] |
Fri, 14 March 2014 19:42 |
Daniel Pitts
Messages: 68 Registered: May 2012
Karma: 0
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Member |
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On 3/12/14 10:18 AM, richard wrote:
> $x=1;
> while ($x<40){
> $yr=range(60,69);
> shuffle($yr);
> $ayr[$x]=$yr[$x];
> echo $ayr[$x]."<br>";
> $x++;
> }
>
>
> I am attempting to load an array based upon the range of numbers 60 through
> 69.
> The array will have 40 items.
> This code produces 9 items just fine.
> The rest of the array is empty.
> What am I missing?
>
for ($x = 1; $x < 40; ++$x) {
$ayr[$x] = rand(60, 69);
}
So much simpler, more efficient, and actually correct.
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Re: Filling an array with random input doesn't quite work [message #185254 is a reply to message #185250] |
Fri, 14 March 2014 22:07 |
Thomas 'PointedEars'
Messages: 701 Registered: October 2010
Karma: 0
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Senior Member |
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Daniel Pitts wrote:
> On 3/12/14 10:18 AM, richard wrote:
>> $x=1;
>> while ($x<40){
>> $yr=range(60,69);
>> shuffle($yr);
>> $ayr[$x]=$yr[$x];
>> echo $ayr[$x]."<br>";
>> $x++;
>> }
>>
>> I am attempting to load an array based upon the range of numbers 60
>> through 69.
>> The array will have 40 items.
>> This code produces 9 items just fine.
>> The rest of the array is empty.
>> What am I missing?
>
> for ($x = 1; $x < 40; ++$x) {
> $ayr[$x] = rand(60, 69);
> }
>
> So much simpler, more efficient, and actually correct.
No, this will produce an array of only 39 elements, assuming there was not
already one. This can be easily fixed, of course.
Still,
$keys = range(1, 40);
$ayr = array_combine($keys, array_map(function () {
return rand(60, 69);
}, $keys)));
is much more elegant :)
PointedEars
--
realism: HTML 4.01 Strict
evangelism: XHTML 1.0 Strict
madness: XHTML 1.1 as application/xhtml+xml
-- Bjoern Hoehrmann
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Re: solved! Re: Filling an array with random input doesn't quite work [message #185257 is a reply to message #185219] |
Fri, 14 March 2014 22:23 |
Thomas 'PointedEars'
Messages: 701 Registered: October 2010
Karma: 0
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Senior Member |
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Christoph Michael Becker wrote:
> Tim Streater wrote:
>> richard <noreply(at)example(dot)com> wrote:
>>> $x=1;
>>> while ($x<40){
>>> $yr=rand(1,10);
>>> $yr=$yr+59;
>>> $num=rand(1,100);
>>> if ($num<100){$num="0".$num;}
>>> if ($num<10){$num="0".$num;}
>>
>> What is the point if this second "if"? You've already covered that with
>> the first.
>
> That serves to add padding to three characters. The last three lines
> could be replaced with the following:
>
> str_pad(rand(1, 100), 3, '0', STR_PAD_LEFT);
$num = str_pad(rand(1, 100), 3, '0', STR_PAD_LEFT);
as str_pad() does not modify strings (because they are immutable).
Or simply
$num = sprintf('%03d', rand(1, 100));
:)
PointedEars
--
Prototype.js was written by people who don't know javascript for people
who don't know javascript. People who don't know javascript are not
the best source of advice on designing systems that use javascript.
-- Richard Cornford, cljs, <f806at$ail$1$8300dec7(at)news(dot)demon(dot)co(dot)uk>
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Re: solved! Re: Filling an array with random input doesn't quite work [message #185258 is a reply to message #185257] |
Fri, 14 March 2014 22:58 |
Christoph Michael Bec
Messages: 207 Registered: June 2013
Karma: 0
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Senior Member |
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Thomas 'PointedEars' Lahn wrote:
> Christoph Michael Becker wrote:
>
>> Tim Streater wrote:
>>> richard <noreply(at)example(dot)com> wrote:
>>>> $x=1;
>>>> while ($x<40){
>>>> $yr=rand(1,10);
>>>> $yr=$yr+59;
>>>> $num=rand(1,100);
>>>> if ($num<100){$num="0".$num;}
>>>> if ($num<10){$num="0".$num;}
>>>
>>> What is the point if this second "if"? You've already covered that with
>>> the first.
>>
>> That serves to add padding to three characters. The last three lines
>> could be replaced with the following:
>>
>> str_pad(rand(1, 100), 3, '0', STR_PAD_LEFT);
>
> $num = str_pad(rand(1, 100), 3, '0', STR_PAD_LEFT);
>
> as str_pad() does not modify strings (because they are immutable).
Of course! Thanks for the correction.
> Or simply
>
> $num = sprintf('%03d', rand(1, 100));
>
> :)
Even better. :)
--
Christoph M. Becker
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Re: Filling an array with random input doesn't quite work [message #185263 is a reply to message #185244] |
Sat, 15 March 2014 03:10 |
Norman Peelman
Messages: 126 Registered: September 2010
Karma: 0
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Senior Member |
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On 03/14/2014 12:55 PM, Jerry Stuckle wrote:
> On 3/14/2014 11:47 AM, Norman Peelman wrote:
>> On 03/14/2014 11:00 AM, Jerry Stuckle wrote:
>>> On 3/14/2014 9:31 AM, Norman Peelman wrote:
>>>> On 03/12/2014 11:11 PM, Jerry Stuckle wrote:
>>>> > On 3/12/2014 11:02 PM, Norman Peelman wrote:
>>>> >> On 03/12/2014 01:18 PM, richard wrote:
>>>> >>> $x=1;
>>>> >>> while ($x<40){
>>>> >>> $yr=range(60,69);
>>>> >>> shuffle($yr);
>>>> >>> $ayr[$x]=$yr[$x];
>>>> >>> echo $ayr[$x]."<br>";
>>>> >>> $x++;
>>>> >>> }
>>>> >>>
>>>> >>>
>>>> >>> I am attempting to load an array based upon the range of numbers 60
>>>> >>> through
>>>> >>> 69.
>>>> >>> The array will have 40 items.
>>>> >>> This code produces 9 items just fine.
>>>> >>> The rest of the array is empty.
>>>> >>> What am I missing?
>>>> >>>
>>>> >>
>>>> >> for ($items=1; $items<=40; $items++)
>>>> >> {
>>>> >> $ayr[$items] = range(60,69);
>>>> >> shuffle(&$ayr[$items]);
>>>> >> }
>>>> >>
>>>> >>
>>>> >
>>>> > Why would you shuffle a single item?
>>>> >
>>>> >
>>>>
>>>> $ayr[$items] is an Array
>>>>
>>>> php > print_r($ayr);
>>>> Array
>>>> (
>>>> [1] => Array
>>>> (
>>>> [0] => 60
>>>> [1] => 61
>>>> [2] => 62
>>>> [3] => 63
>>>> [4] => 64
>>>> [5] => 65
>>>> [6] => 66
>>>> [7] => 67
>>>> [8] => 68
>>>> [9] => 69
>>>> )
>>>>
>>>> )
>>>>
>>>> ... after Shuffle:
>>>>
>>>> php > shuffle(&$ayr[1]);
>>>> php > print_r($ayr[1]);
>>>> Array
>>>> (
>>>> [0] => 67
>>>> [1] => 69
>>>> [2] => 66
>>>> [3] => 61
>>>> [4] => 62
>>>> [5] => 60
>>>> [6] => 64
>>>> [7] => 68
>>>> [8] => 63
>>>> [9] => 65
>>>> )
>>>>
>>>>
>>>>
>>>
>>> Sorry, I was in a hurry and wasn't paying as much attention.
>>>
>>> But then why have 40 different arrays of 10 items each, anyway?
>>>
>>
>> I don't even know why there are 40 items when you are pulling from a
>> selection of 10 - there's going to be duplicates. Maybe that doesn't
>> matter... I think someone else actually had what Richard was really
>> after.
>>
>>
>>
>
> But each item in your list is an array. He wants single values.
>
>
Now that I checked his page I see what he was after.
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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Re: Filling an array with random input doesn't quite work [message #185265 is a reply to message #185254] |
Sat, 15 March 2014 21:32 |
Ben Bacarisse
Messages: 82 Registered: November 2013
Karma: 0
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Member |
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Thomas 'PointedEars' Lahn <PointedEars(at)web(dot)de> writes:
> Daniel Pitts wrote:
>
>> On 3/12/14 10:18 AM, richard wrote:
>>> $x=1;
>>> while ($x<40){
>>> $yr=range(60,69);
>>> shuffle($yr);
>>> $ayr[$x]=$yr[$x];
>>> echo $ayr[$x]."<br>";
>>> $x++;
>>> }
>>>
>>> I am attempting to load an array based upon the range of numbers 60
>>> through 69.
>>> The array will have 40 items.
>>> This code produces 9 items just fine.
>>> The rest of the array is empty.
>>> What am I missing?
>>
>> for ($x = 1; $x < 40; ++$x) {
>> $ayr[$x] = rand(60, 69);
>> }
>>
>> So much simpler, more efficient, and actually correct.
>
> No, this will produce an array of only 39 elements, assuming there was not
> already one. This can be easily fixed, of course.
>
> Still,
>
> $keys = range(1, 40);
> $ayr = array_combine($keys, array_map(function () {
> return rand(60, 69);
> }, $keys)));
>
> is much more elegant :)
Yes, but it's a shame about the extra ')'. I think
$ayr = array_map(function () { return rand(60, 69); },
array_fill(1, 40, null));
is a little simpler.
--
Ben.
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Re: Filling an array with random input doesn't quite work [message #185266 is a reply to message #185265] |
Sat, 15 March 2014 22:14 |
Thomas 'PointedEars'
Messages: 701 Registered: October 2010
Karma: 0
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Senior Member |
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Ben Bacarisse wrote:
> Thomas 'PointedEars' Lahn <PointedEars(at)web(dot)de> writes:
>> Daniel Pitts wrote:
>>> for ($x = 1; $x < 40; ++$x) {
>>> $ayr[$x] = rand(60, 69);
>>> }
>>>
>>> So much simpler, more efficient, and actually correct.
>>
>> No, this will produce an array of only 39 elements, assuming there was
>> not already one. This can be easily fixed, of course.
>>
>> Still,
>>
>> $keys = range(1, 40);
>> $ayr = array_combine($keys, array_map(function () {
>> return rand(60, 69);
>> }, $keys)));
>>
>> is much more elegant :)
>
> Yes, but it's a shame about the extra ')'.
Ah, yes, no idea how that got in there. Should have been
$keys = range(1, 40);
$ayr = array_combine($keys, array_map(function () {
return rand(60, 69);
}, $keys));
> I think
>
> $ayr = array_map(function () { return rand(60, 69); },
> array_fill(1, 40, null));
>
> is a little simpler.
ACK. Actually, I had experimented with array_fill() but, strangely enough,
I overlooked this possibility. (I had posted something similar with regard
to letters not long ago.)
PointedEars
--
Prototype.js was written by people who don't know javascript for people
who don't know javascript. People who don't know javascript are not
the best source of advice on designing systems that use javascript.
-- Richard Cornford, cljs, <f806at$ail$1$8300dec7(at)news(dot)demon(dot)co(dot)uk>
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Re: Filling an array with random input doesn't quite work [message #185267 is a reply to message #185265] |
Sun, 16 March 2014 02:14 |
Jerry Stuckle
Messages: 2598 Registered: September 2010
Karma: 0
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Senior Member |
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On 3/15/2014 5:32 PM, Ben Bacarisse wrote:
> Thomas 'PointedEars' Lahn <PointedEars(at)web(dot)de> writes:
>
>> Daniel Pitts wrote:
>>
>>> On 3/12/14 10:18 AM, richard wrote:
>>>> $x=1;
>>>> while ($x<40){
>>>> $yr=range(60,69);
>>>> shuffle($yr);
>>>> $ayr[$x]=$yr[$x];
>>>> echo $ayr[$x]."<br>";
>>>> $x++;
>>>> }
>>>>
>>>> I am attempting to load an array based upon the range of numbers 60
>>>> through 69.
>>>> The array will have 40 items.
>>>> This code produces 9 items just fine.
>>>> The rest of the array is empty.
>>>> What am I missing?
>>>
>>> for ($x = 1; $x < 40; ++$x) {
>>> $ayr[$x] = rand(60, 69);
>>> }
>>>
>>> So much simpler, more efficient, and actually correct.
>>
>> No, this will produce an array of only 39 elements, assuming there was not
>> already one. This can be easily fixed, of course.
>>
>> Still,
>>
>> $keys = range(1, 40);
>> $ayr = array_combine($keys, array_map(function () {
>> return rand(60, 69);
>> }, $keys)));
>>
>> is much more elegant :)
>
> Yes, but it's a shame about the extra ')'. I think
>
> $ayr = array_map(function () { return rand(60, 69); },
> array_fill(1, 40, null));
>
> is a little simpler.
>
Shorter, maybe - but arguably NOT simpler. Hand that code to a new PHP
programmer and he/she will have no idea.
It's generally better to code for clarity first.
--
==================
Remove the "x" from my email address
Jerry Stuckle
jstucklex(at)attglobal(dot)net
==================
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Re: Filling an array with random input doesn't quite work [message #185268 is a reply to message #185267] |
Sun, 16 March 2014 02:51 |
Ben Bacarisse
Messages: 82 Registered: November 2013
Karma: 0
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Member |
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|
Jerry Stuckle <jstucklex(at)attglobal(dot)net> writes:
> On 3/15/2014 5:32 PM, Ben Bacarisse wrote:
>> Thomas 'PointedEars' Lahn <PointedEars(at)web(dot)de> writes:
>>
>>> Daniel Pitts wrote:
<snip>
>>>> for ($x = 1; $x < 40; ++$x) {
>>>> $ayr[$x] = rand(60, 69);
>>>> }
>>>>
>>>> So much simpler, more efficient, and actually correct.
>>>
>>> No, this will produce an array of only 39 elements, assuming there was not
>>> already one. This can be easily fixed, of course.
>>>
>>> Still,
>>>
>>> $keys = range(1, 40);
>>> $ayr = array_combine($keys, array_map(function () {
>>> return rand(60, 69);
>>> }, $keys)));
>>>
>>> is much more elegant :)
>>
>> Yes, but it's a shame about the extra ')'. I think
>>
>> $ayr = array_map(function () { return rand(60, 69); },
>> array_fill(1, 40, null));
>>
>> is a little simpler.
>>
>
> Shorter, maybe - but arguably NOT simpler. Hand that code to a new
> PHP programmer and he/she will have no idea.
Surely that would depend on their background would it not? Anyway, I
meant simpler that the version using array_combine and array_map.
> It's generally better to code for clarity first.
Yes, I agree, but clarity is not an absolute, and aiming to be clear to
beginners puts considerable constraints on design and coding.
--
Ben.
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Re: Filling an array with random input doesn't quite work [message #185270 is a reply to message #185268] |
Sun, 16 March 2014 13:46 |
Jerry Stuckle
Messages: 2598 Registered: September 2010
Karma: 0
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Senior Member |
|
|
On 3/15/2014 10:51 PM, Ben Bacarisse wrote:
> Jerry Stuckle <jstucklex(at)attglobal(dot)net> writes:
>
>> On 3/15/2014 5:32 PM, Ben Bacarisse wrote:
>>> Thomas 'PointedEars' Lahn <PointedEars(at)web(dot)de> writes:
>>>
>>>> Daniel Pitts wrote:
> <snip>
>>>> > for ($x = 1; $x < 40; ++$x) {
>>>> > $ayr[$x] = rand(60, 69);
>>>> > }
>>>> >
>>>> > So much simpler, more efficient, and actually correct.
>>>>
>>>> No, this will produce an array of only 39 elements, assuming there was not
>>>> already one. This can be easily fixed, of course.
>>>>
>>>> Still,
>>>>
>>>> $keys = range(1, 40);
>>>> $ayr = array_combine($keys, array_map(function () {
>>>> return rand(60, 69);
>>>> }, $keys)));
>>>>
>>>> is much more elegant :)
>>>
>>> Yes, but it's a shame about the extra ')'. I think
>>>
>>> $ayr = array_map(function () { return rand(60, 69); },
>>> array_fill(1, 40, null));
>>>
>>> is a little simpler.
>>>
>>
>> Shorter, maybe - but arguably NOT simpler. Hand that code to a new
>> PHP programmer and he/she will have no idea.
>
> Surely that would depend on their background would it not? Anyway, I
> meant simpler that the version using array_combine and array_map.
>
No, it does not. You may not be the only one looking at it.
>> It's generally better to code for clarity first.
>
> Yes, I agree, but clarity is not an absolute, and aiming to be clear to
> beginners puts considerable constraints on design and coding.
>
Not at all. But not being able to be clear in coding shows a lack of
good programming skills.
--
==================
Remove the "x" from my email address
Jerry Stuckle
jstucklex(at)attglobal(dot)net
==================
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Re: Filling an array with random input doesn't quite work [message #185273 is a reply to message #185211] |
Sun, 16 March 2014 14:45 |
Gabriel
Messages: 11 Registered: March 2014
Karma: 0
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Junior Member |
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On 12/03/2014 17:18, richard wrote:
> $x=1;
> while ($x<40){
> $yr=range(60,69);
> shuffle($yr);
> $ayr[$x]=$yr[$x];
> echo $ayr[$x]."<br>";
> $x++;
> }
>
>
> I am attempting to load an array based upon the range of numbers 60 through
> 69.
> The array will have 40 items.
> This code produces 9 items just fine.
> The rest of the array is empty.
> What am I missing?
>
I would do it like this:
$arr = array_fill(0, 40, 0);
array_walk($arr, function(&$v, $k) { $v = rand(60, 69); });
That will provide you with an array containing 40 elements, each a
random integer between 60 and 69:
print_r($arr);
Array
(
[0] => 60
[1] => 69
[2] => 63
[3] => 63
[4] => 64
[5] => 65
[6] => 68
[7] => 67
[8] => 67
[9] => 67
[10] => 63
[11] => 69
[12] => 65
[13] => 60
[14] => 68
[15] => 62
[16] => 67
[17] => 65
[18] => 60
[19] => 65
[20] => 62
[21] => 69
[22] => 69
[23] => 64
[24] => 68
[25] => 65
[26] => 69
[27] => 66
[28] => 61
[29] => 69
[30] => 61
[31] => 61
[32] => 68
[33] => 64
[34] => 64
[35] => 63
[36] => 60
[37] => 63
[38] => 60
[39] => 67
)
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Re: Filling an array with random input doesn't quite work [message #185286 is a reply to message #185273] |
Sun, 16 March 2014 23:52 |
Norman Peelman
Messages: 126 Registered: September 2010
Karma: 0
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Senior Member |
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On 03/16/2014 10:45 AM, Gabriel Dragffy wrote:
> On 12/03/2014 17:18, richard wrote:
>> $x=1;
>> while ($x<40){
>> $yr=range(60,69);
>> shuffle($yr);
>> $ayr[$x]=$yr[$x];
>> echo $ayr[$x]."<br>";
>> $x++;
>> }
>>
>>
>> I am attempting to load an array based upon the range of numbers 60
>> through
>> 69.
>> The array will have 40 items.
>> This code produces 9 items just fine.
>> The rest of the array is empty.
>> What am I missing?
>>
>
> I would do it like this:
>
> $arr = array_fill(0, 40, 0);
> array_walk($arr, function(&$v, $k) { $v = rand(60, 69); });
>
> That will provide you with an array containing 40 elements, each a
> random integer between 60 and 69:
>
>
> print_r($arr);
> Array
> (
> [0] => 60
> [1] => 69
> [2] => 63
> [3] => 63
> [4] => 64
> [5] => 65
> [6] => 68
> [7] => 67
> [8] => 67
> [9] => 67
> [10] => 63
> [11] => 69
> [12] => 65
> [13] => 60
> [14] => 68
> [15] => 62
> [16] => 67
> [17] => 65
> [18] => 60
> [19] => 65
> [20] => 62
> [21] => 69
> [22] => 69
> [23] => 64
> [24] => 68
> [25] => 65
> [26] => 69
> [27] => 66
> [28] => 61
> [29] => 69
> [30] => 61
> [31] => 61
> [32] => 68
> [33] => 64
> [34] => 64
> [35] => 63
> [36] => 60
> [37] => 63
> [38] => 60
> [39] => 67
> )
Nice!
--
Norman
Registered Linux user #461062
-Have you been to www.php.net yet?-
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Re: Filling an array with random input doesn't quite work [message #185294 is a reply to message #185273] |
Mon, 17 March 2014 02:16 |
Denis McMahon
Messages: 634 Registered: September 2010
Karma: 0
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Senior Member |
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On Sun, 16 Mar 2014 14:45:42 +0000, Gabriel Dragffy wrote:
> On 12/03/2014 17:18, richard wrote:
>> $x=1;
>> while ($x<40){
>> $yr=range(60,69); shuffle($yr); $ayr[$x]=$yr[$x]; echo
>> $ayr[$x]."<br>";
>> $x++;
>> }
>>
>>
>> I am attempting to load an array based upon the range of numbers 60
>> through 69.
>> The array will have 40 items.
>> This code produces 9 items just fine.
>> The rest of the array is empty.
>> What am I missing?
>>
>>
> I would do it like this:
>
> $arr = array_fill(0, 40, 0);
> array_walk($arr, function(&$v, $k) { $v = rand(60, 69); });
>
> That will provide you with an array containing 40 elements, each a
> random integer between 60 and 69:
>
>
> print_r($arr);
> Array (
> [0] => 60 [1] => 69 [2] => 63 [3] => 63 [4] => 64 [5] => 65 [6] =>
> 68 [7] => 67 [8] => 67 [9] => 67 [10] => 63 [11] => 69 [12] => 65
> [13] => 60 [14] => 68 [15] => 62 [16] => 67 [17] => 65 [18] => 60
> [19] => 65 [20] => 62 [21] => 69 [22] => 69 [23] => 64 [24] => 68
> [25] => 65 [26] => 69 [27] => 66 [28] => 61 [29] => 69 [30] => 61
> [31] => 61 [32] => 68 [33] => 64 [34] => 64 [35] => 63 [36] => 60
> [37] => 63 [38] => 60 [39] => 67
> )
Yes, but what he wants is actually something like:
Array
(
[39] => http://mroldies.net/audio/1966/66-033.mp3
[38] => http://mroldies.net/audio/1964/64-012.mp3
[37] => http://mroldies.net/audio/1963/63-085.mp3
[36] => http://mroldies.net/audio/1960/60-014.mp3
[35] => http://mroldies.net/audio/1960/60-011.mp3
[34] => http://mroldies.net/audio/1964/64-065.mp3
[33] => http://mroldies.net/audio/1961/61-058.mp3
[32] => http://mroldies.net/audio/1960/60-026.mp3
[31] => http://mroldies.net/audio/1964/64-090.mp3
[30] => http://mroldies.net/audio/1961/61-080.mp3
[29] => http://mroldies.net/audio/1966/66-059.mp3
[28] => http://mroldies.net/audio/1963/63-066.mp3
[27] => http://mroldies.net/audio/1965/65-006.mp3
[26] => http://mroldies.net/audio/1966/66-050.mp3
[25] => http://mroldies.net/audio/1969/69-004.mp3
[24] => http://mroldies.net/audio/1963/63-100.mp3
[23] => http://mroldies.net/audio/1961/61-071.mp3
[22] => http://mroldies.net/audio/1969/69-082.mp3
[21] => http://mroldies.net/audio/1962/62-075.mp3
[20] => http://mroldies.net/audio/1969/69-080.mp3
[19] => http://mroldies.net/audio/1963/63-039.mp3
[18] => http://mroldies.net/audio/1963/63-022.mp3
[17] => http://mroldies.net/audio/1967/67-096.mp3
[16] => http://mroldies.net/audio/1961/61-041.mp3
[15] => http://mroldies.net/audio/1960/60-013.mp3
[14] => http://mroldies.net/audio/1969/69-012.mp3
[13] => http://mroldies.net/audio/1967/67-087.mp3
[12] => http://mroldies.net/audio/1961/61-009.mp3
[11] => http://mroldies.net/audio/1967/67-044.mp3
[10] => http://mroldies.net/audio/1960/60-021.mp3
[9] => http://mroldies.net/audio/1965/65-094.mp3
[8] => http://mroldies.net/audio/1961/61-071.mp3
[7] => http://mroldies.net/audio/1967/67-040.mp3
[6] => http://mroldies.net/audio/1967/67-044.mp3
[5] => http://mroldies.net/audio/1967/67-081.mp3
[4] => http://mroldies.net/audio/1962/62-022.mp3
[3] => http://mroldies.net/audio/1966/66-017.mp3
[2] => http://mroldies.net/audio/1965/65-005.mp3
[1] => http://mroldies.net/audio/1963/63-076.mp3
)
(although I suspect that he really wants either indexes 1 .. 40 or 0 ..
39, but it's hard to tell which he wants from his code.
Hence my solution of:
$x=40;
$song=array();
while(--$x)$song[$x]=sprintf("http://mroldies.net/audio/19%d/%d-%03d.mp3",
$y=rand(60,69),$y,rand(1,100));
--
Denis McMahon, denismfmcmahon(at)gmail(dot)com
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Re: Filling an array with random input doesn't quite work [message #185304 is a reply to message #185294] |
Mon, 17 March 2014 12:43 |
Gabriel
Messages: 11 Registered: March 2014
Karma: 0
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Junior Member |
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On 2014-03-17 02:16:24 +0000, Denis McMahon said:
>> I would do it like this:
>>
>> $arr = array_fill(0, 40, 0);
>> array_walk($arr, function(&$v, $k) { $v = rand(60, 69); });
>>
>> That will provide you with an array containing 40 elements, each a
>> random integer between 60 and 69:
>>
>>
>> print_r($arr);
>> Array (
>> [0] => 60 [1] => 69 [2] => 63 [3] => 63 [4] => 64 [5] => 65 [6] =>
>> 68 [7] => 67 [8] => 67 [9] => 67 [10] => 63 [11] => 69 [12] => 65
>> [13] => 60 [14] => 68 [15] => 62 [16] => 67 [17] => 65 [18] => 60
>> [19] => 65 [20] => 62 [21] => 69 [22] => 69 [23] => 64 [24] => 68
>> [25] => 65 [26] => 69 [27] => 66 [28] => 61 [29] => 69 [30] => 61
>> [31] => 61 [32] => 68 [33] => 64 [34] => 64 [35] => 63 [36] => 60
>> [37] => 63 [38] => 60 [39] => 67
>> )
>
> Yes, but what he wants is actually something like:
>
> Array
> (
> [39] => http://mroldies.net/audio/1966/66-033.mp3
> [38] => http://mroldies.net/audio/1964/64-012.mp3
> [37] => http://mroldies.net/audio/1963/63-085.mp3
> [36] => http://mroldies.net/audio/1960/60-014.mp3
> [35] => http://mroldies.net/audio/1960/60-011.mp3
> [34] => http://mroldies.net/audio/1964/64-065.mp3
Thank you for pointing that out, Dennis.
My code can be trivially modified to do this:
$arr = array_fill(0, 40, 'http://mroldies.net/audio/19%u/%u-%03u.mp3');
array_walk($arr, function(&$v, $k) { $yr = rand(60, 69); $v =
sprintf($v, $yr, $yr, rand(1, 100)); });
Will yield the following array which I have cut short to reduce noise:
print_r($arr);
Array
(
[0] => http://mroldies.net/audio/1966/66-007.mp3
[1] => http://mroldies.net/audio/1967/67-021.mp3
[2] => http://mroldies.net/audio/1962/62-016.mp3
[…]
)
Each person prefers their own solution and I am no different. I prefer
mine because I find it readable whilst only requiring two lines, of
course you could add a few more line breaks in if preferable. The
highlights for me are utilising a PHP native function to walk the array
instead of writing your own iterator using some form of while or for
loop, a lambda function for the processing, and the fantastic
formatting abilities of sprintf.
Cheers
Gabe
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Re: Filling an array with random input doesn't quite work [message #185305 is a reply to message #185304] |
Mon, 17 March 2014 12:52 |
Jerry Stuckle
Messages: 2598 Registered: September 2010
Karma: 0
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Senior Member |
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On 3/17/2014 8:43 AM, Gabe wrote:
> On 2014-03-17 02:16:24 +0000, Denis McMahon said:
>
>>> I would do it like this:
>>>
>>> $arr = array_fill(0, 40, 0);
>>> array_walk($arr, function(&$v, $k) { $v = rand(60, 69); });
>>>
>>> That will provide you with an array containing 40 elements, each a
>>> random integer between 60 and 69:
>>>
>>>
>>> print_r($arr);
>>> Array (
>>> [0] => 60 [1] => 69 [2] => 63 [3] => 63 [4] => 64 [5] => 65 [6] =>
>>> 68 [7] => 67 [8] => 67 [9] => 67 [10] => 63 [11] => 69 [12] => 65
>>> [13] => 60 [14] => 68 [15] => 62 [16] => 67 [17] => 65 [18] => 60
>>> [19] => 65 [20] => 62 [21] => 69 [22] => 69 [23] => 64 [24] => 68
>>> [25] => 65 [26] => 69 [27] => 66 [28] => 61 [29] => 69 [30] => 61
>>> [31] => 61 [32] => 68 [33] => 64 [34] => 64 [35] => 63 [36] => 60
>>> [37] => 63 [38] => 60 [39] => 67
>>> )
>>
>> Yes, but what he wants is actually something like:
>>
>> Array
>> (
>> [39] => http://mroldies.net/audio/1966/66-033.mp3
>> [38] => http://mroldies.net/audio/1964/64-012.mp3
>> [37] => http://mroldies.net/audio/1963/63-085.mp3
>> [36] => http://mroldies.net/audio/1960/60-014.mp3
>> [35] => http://mroldies.net/audio/1960/60-011.mp3
>> [34] => http://mroldies.net/audio/1964/64-065.mp3
>
> Thank you for pointing that out, Dennis.
>
> My code can be trivially modified to do this:
>
>
> $arr = array_fill(0, 40, 'http://mroldies.net/audio/19%u/%u-%03u.mp3');
> array_walk($arr, function(&$v, $k) { $yr = rand(60, 69); $v =
> sprintf($v, $yr, $yr, rand(1, 100)); });
>
>
> Will yield the following array which I have cut short to reduce noise:
>
> print_r($arr);
> Array
> (
> [0] => http://mroldies.net/audio/1966/66-007.mp3
> [1] => http://mroldies.net/audio/1967/67-021.mp3
> [2] => http://mroldies.net/audio/1962/62-016.mp3
> […]
> )
>
> Each person prefers their own solution and I am no different. I prefer
> mine because I find it readable whilst only requiring two lines, of
> course you could add a few more line breaks in if preferable. The
> highlights for me are utilising a PHP native function to walk the array
> instead of writing your own iterator using some form of while or for
> loop, a lambda function for the processing, and the fantastic formatting
> abilities of sprintf.
>
> Cheers
>
> Gabe
>
The question here is not whether YOU find it readable - does the NEW GUY
find it readable?
I've seen more bugs in code because people try to get fancy or short
than when they try to be clear. Good programmers understand this.
--
==================
Remove the "x" from my email address
Jerry Stuckle
jstucklex(at)attglobal(dot)net
==================
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Re: Filling an array with random input doesn't quite work [message #185306 is a reply to message #185304] |
Mon, 17 March 2014 13:32 |
Thomas 'PointedEars'
Messages: 701 Registered: October 2010
Karma: 0
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Senior Member |
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Gabe wrote:
^^^^
Please fix.
> On 2014-03-17 02:16:24 +0000, Denis McMahon said:
>>> I would do it like this:
>>>
>>> $arr = array_fill(0, 40, 0);
>>> array_walk($arr, function(&$v, $k) { $v = rand(60, 69); });
>>>
>>> That will provide you with an array containing 40 elements, each a
>>> random integer between 60 and 69:
>>>
>>>
>>> print_r($arr);
>>> Array (
>>> [0] => 60 [1] => 69 [2] => 63 [3] => 63 [4] => 64 [5] => 65 [6] =>
>>> 68 [7] => 67 [8] => 67 [9] => 67 [10] => 63 [11] => 69 [12] => 65
>>> [13] => 60 [14] => 68 [15] => 62 [16] => 67 [17] => 65 [18] => 60
>>> [19] => 65 [20] => 62 [21] => 69 [22] => 69 [23] => 64 [24] => 68
>>> [25] => 65 [26] => 69 [27] => 66 [28] => 61 [29] => 69 [30] => 61
>>> [31] => 61 [32] => 68 [33] => 64 [34] => 64 [35] => 63 [36] => 60
>>> [37] => 63 [38] => 60 [39] => 67
>>> )
>>
>> Yes, but what he wants is actually something like:
>>
>> Array
>> (
>> [39] => http://mroldies.net/audio/1966/66-033.mp3
>> [38] => http://mroldies.net/audio/1964/64-012.mp3
>> [37] => http://mroldies.net/audio/1963/63-085.mp3
>> [36] => http://mroldies.net/audio/1960/60-014.mp3
>> [35] => http://mroldies.net/audio/1960/60-011.mp3
>> [34] => http://mroldies.net/audio/1964/64-065.mp3
>
> Thank you for pointing that out, Dennis.
>
> My code can be trivially modified to do this:
>
>
> $arr = array_fill(0, 40, 'http://mroldies.net/audio/19%u/%u-%03u.mp3');
> array_walk($arr, function(&$v, $k) { $yr = rand(60, 69); $v =
> sprintf($v, $yr, $yr, rand(1, 100)); });
>
>
> Will yield the following array which I have cut short to reduce noise:
>
> print_r($arr);
> Array
> (
> [0] => http://mroldies.net/audio/1966/66-007.mp3
> [1] => http://mroldies.net/audio/1967/67-021.mp3
> [2] => http://mroldies.net/audio/1962/62-016.mp3
> […]
> )
Which *still* is _not_ what was asked for, which is (for whatever reason)
keys from _1_ to _40_ inclusive.
It is also less than optimal to store the repeating prefix in the array, but
you might only have gotten the idea that this was wanted from the precursor.
> Each person prefers their own solution and I am no different. I prefer
> mine because I find it readable whilst only requiring two lines, of
> course you could add a few more line breaks in if preferable. […]
You are missing the point.
PointedEars
--
var bugRiddenCrashPronePieceOfJunk = (
navigator.userAgent.indexOf('MSIE 5') != -1
&& navigator.userAgent.indexOf('Mac') != -1
) // Plone, register_function.js:16
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Re: Filling an array with random input doesn't quite work [message #185307 is a reply to message #185306] |
Mon, 17 March 2014 13:47 |
Gabriel
Messages: 11 Registered: March 2014
Karma: 0
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Junior Member |
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On 2014-03-17 13:32:57 +0000, Thomas 'PointedEars' Lahn said:
> Gabe wrote:
> ^^^^
> Please fix.
>
>> On 2014-03-17 02:16:24 +0000, Denis McMahon said:
>>>> I would do it like this:
>>>>
>>>> $arr = array_fill(0, 40, 0);
>>>> array_walk($arr, function(&$v, $k) { $v = rand(60, 69); });
>>>>
>>>> That will provide you with an array containing 40 elements, each a
>>>> random integer between 60 and 69:
>>>>
>>>>
>>>> print_r($arr);
>>>> Array (
>>>> [0] => 60 [1] => 69 [2] => 63 [3] => 63 [4] => 64 [5] => 65 [6] =>
>>>> 68 [7] => 67 [8] => 67 [9] => 67 [10] => 63 [11] => 69 [12] => 65
>>>> [13] => 60 [14] => 68 [15] => 62 [16] => 67 [17] => 65 [18] => 60
>>>> [19] => 65 [20] => 62 [21] => 69 [22] => 69 [23] => 64 [24] => 68
>>>> [25] => 65 [26] => 69 [27] => 66 [28] => 61 [29] => 69 [30] => 61
>>>> [31] => 61 [32] => 68 [33] => 64 [34] => 64 [35] => 63 [36] => 60
>>>> [37] => 63 [38] => 60 [39] => 67
>>>> )
>>>
>>> Yes, but what he wants is actually something like:
>>>
>>> Array
>>> (
>>> [39] => http://mroldies.net/audio/1966/66-033.mp3
>>> [38] => http://mroldies.net/audio/1964/64-012.mp3
>>> [37] => http://mroldies.net/audio/1963/63-085.mp3
>>> [36] => http://mroldies.net/audio/1960/60-014.mp3
>>> [35] => http://mroldies.net/audio/1960/60-011.mp3
>>> [34] => http://mroldies.net/audio/1964/64-065.mp3
>>
>> Thank you for pointing that out, Dennis.
>>
>> My code can be trivially modified to do this:
>>
>>
>> $arr = array_fill(0, 40, 'http://mroldies.net/audio/19%u/%u-%03u.mp3');
>> array_walk($arr, function(&$v, $k) { $yr = rand(60, 69); $v =
>> sprintf($v, $yr, $yr, rand(1, 100)); });
>>
>>
>> Will yield the following array which I have cut short to reduce noise:
>>
>> print_r($arr);
>> Array
>> (
>> [0] => http://mroldies.net/audio/1966/66-007.mp3
>> [1] => http://mroldies.net/audio/1967/67-021.mp3
>> [2] => http://mroldies.net/audio/1962/62-016.mp3
>> […]
>> )
>
> Which *still* is _not_ what was asked for, which is (for whatever reason)
> keys from _1_ to _40_ inclusive.
>
> It is also less than optimal to store the repeating prefix in the array, but
> you might only have gotten the idea that this was wanted from the precursor.
>
>> Each person prefers their own solution and I am no different. I prefer
>> mine because I find it readable whilst only requiring two lines, of
>> course you could add a few more line breaks in if preferable. […]
>
> You are missing the point.
>
>
> PointedEars
Dear PointedEars
I am so sorry - I sometimes assume that people (on a PHP dev mailing
list) would be able to make very basic adjustments to snippets that I
posted to accommodate for discrepencies. I take it you are not one and
have not programmed PHP before and are just looking to get started.
Allow me to show you how to make such a change in order to produce an
array index 1 to 40 inclusive… You will need to change:
$arr = array_fill(0, 40, 'http://mroldies.net/audio/19%u/%u-%03u.mp3');
to
$arr = array_fill(1, 40, 'http://mroldies.net/audio/19%u/%u-%03u.mp3');
There is no problem storing a repeated prefix in the initial array as
the output array will contain it anyway. Since the value is replaced
in-situ memory usage would be approximately the same. Infact there is
only one array that is programmatically manipulated. If the URL is not
required to be stored in the array then please ask me for help again
and I will be glad to show you how to delete the characters comprising
the URL from the snippet.
Cheers
Gabe
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Re: Filling an array with random input doesn't quite work [message #185311 is a reply to message #185307] |
Mon, 17 March 2014 15:07 |
Thomas 'PointedEars'
Messages: 701 Registered: October 2010
Karma: 0
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Senior Member |
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Gabe wrote:
> On 2014-03-17 13:32:57 +0000, Thomas 'PointedEars' Lahn said:
>> Gabe wrote:
>> ^^^^
>>> My code can be trivially modified to do this:
>>>
>>>
>>> $arr = array_fill(0, 40, 'http://mroldies.net/audio/19%u/%u-%03u.mp3');
>>> array_walk($arr, function(&$v, $k) { $yr = rand(60, 69); $v =
>>> sprintf($v, $yr, $yr, rand(1, 100)); });
>>>
>>>
>>> Will yield the following array which I have cut short to reduce noise:
>>>
>>> print_r($arr);
>>> Array
>>> (
>>> [0] => http://mroldies.net/audio/1966/66-007.mp3
>>> [1] => http://mroldies.net/audio/1967/67-021.mp3
>>> [2] => http://mroldies.net/audio/1962/62-016.mp3
>>> […]
>>> )
>>
>> Which *still* is _not_ what was asked for, which is (for whatever reason)
>> keys from _1_ to _40_ inclusive.
>>
>> It is also less than optimal to store the repeating prefix in the array,
>> but you might only have gotten the idea that this was wanted from the
>> precursor.
>>
>>> Each person prefers their own solution and I am no different. I prefer
>>> mine because I find it readable whilst only requiring two lines, of
>>> course you could add a few more line breaks in if preferable. […]
>>
>> You are missing the point.
>>
>>
>> PointedEars
It is impolite to full-quote a posting, particularly to quote the signature
of a posting without referring to it. Learn to quote.
> Dear PointedEars
You are confusing this with private e-mail.
> I am so sorry - I sometimes assume that people (on a PHP dev mailing
> list)
This is not a mailing list, it is a Usenet newsgroup. But it makes no
significant difference in that regard:
> would be able to make very basic adjustments to snippets that I
> posted to accommodate for discrepencies.
You have posted *twice* now something that fails to address the problem at
hand. You have been notified of that twice now. You have posted a
correction that is suboptimal, and you have been notified of that. And you
of all people dare to patronize others? Go away.
> I take it you are not one and have not programmed PHP before and are just
> looking to get started.
I have more than 14 years of professional experience in software development
with PHP now.
> Allow me to show you how to make such a change in order to produce an
> array index 1 to 40 inclusive… […]
If you cared to read, *I* know how it is done.
Score adjusted
PointedEars
--
realism: HTML 4.01 Strict
evangelism: XHTML 1.0 Strict
madness: XHTML 1.1 as application/xhtml+xml
-- Bjoern Hoehrmann
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