| Re: echo other way to output a constant? [message #169482 is a reply to message #169476] |
Wed, 15 September 2010 01:25   |
Peter H. Coffin
Messages: 245
Registered: September 2010
Karma:
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Senior Member |
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On Tue, 14 Sep 2010 17:12:38 -0500, MikeB wrote:
> Say I have the following code:
>
> <?php
>
>
> define('MAX_FILE_SIZE', 300);
>
> echo <<<_END
> <html><head><title>PHP Form Upload</title></head><body>
> <form method='post' action='UploadFile2.php' enctype='multipart/form-data'>
> <!-- MAX_FILE_SIZE must precede the file input field -->
> <input type="hidden" name="MAX_FILE_SIZE" value="" />
> Select a JPG, GIF, PNG or TIF File:
> <input type='file' name='filename' size='60' />
> <br/><input type='submit' value='Upload' /></form>
> _END;
>
> echo "</body></html>";
> ?>
>
> How can I get PHP to place the value of the constant MAX_FILE_SIZE in
> the value attribute for the hidden field MAX_FILE_SIZE?
>
> Since it does not start with a $-sign it is not interpreted as a
> variable. I tried putting it in curly braces {}, which sometimes work,
> but that didn't do the trick either.
>
> I was hoping that print_r() would do it, but I could not get PHP to
> interpret that either.
>
> So any way or do I have to a) put the constant in a variable or b) echo
> each line individually so that I can do concatenation of the output lines?
PHP puts responses to forms sent using method post into a special array
called "_POST". So, to get at the contents of an input control called
"MAX_FILE_SIZE", you use the variable $_POST['MAX_FILE_SIZE']. There is
some trickiness with input types that can return multiple values, but we
can get to that once you've gotten the above bits working and are
comfortable with them.
--
The Write Many, Read Never drive. For those people that don't know
their system has a /dev/null already.
-- Rik Steenwinkel, singing the praises of 8mm Exabytes
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