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Re: mysql_fetch_array [message #169804 is a reply to message #169797] Mon, 27 September 2010 12:23 Go to previous messageGo to previous message
sheldonlg is currently offline  sheldonlg
Messages: 166
Registered: September 2010
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On 9/27/2010 3:15 AM, The Natural Philosopher wrote:
> sheldonlg wrote:
>> On 9/26/2010 7:44 AM, Captain Paralytic wrote:
>>> On Sep 26, 12:36 am, MikeB<mpbr...@gmail.com> wrote:
>>>> Captain Paralytic wrote:
>>>> > On Sep 25, 9:28 pm, MikeB<mpbr...@gmail.com> wrote:
>>>> >> I have the following code:
>>>> <snip>
>>>>
>>>> >> What PHP magic is at work here?
>>>>
>>>> >> Thanks.
>>>>
>>>> > I can recommend reading:
>>>> > http://php.net/manual/en/language.types.array.php
>>>>
>>>> I've read that page before, but only now the following sentence makes
>>>> sense:
>>>>
>>>> "If a key is not specified for a value, the maximum of the integer
>>>> indices is taken and the new key will be that value plus 1. If a key
>>>> that already has an assigned value is specified, that value will be
>>>> overwritten. "
>>>
>>> I was referring to the section just below headed:
>>> "Creating/modifying with square bracket syntax"
>>> but the paragraph that you mentioned certainly explains more of the
>>> actual details.
>>
>> You know, that ("the maximum of the integer indices is taken and the
>> new key will be that value plus 1") is possibly a misleading clause.
>>
>> For example:
>>
>> $results = array();
>> $results[] = 'First One';
>>
>> Reading that clause, "the maximum of the integer indices is taken and
>> the new key will be that value plus 1", one might expect the index of
>> "First One" to be 1. In fact, of course, it is 0. IOW, if there is no
>> index yet, then it doesn't add 1, but takes the first one as 0.
>>
> Ah, but the maximum index value of a non existent array is therefore
> obviously -1. :-)
>

Try to get that from reading that sentence!

--
Shelly
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