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Re: mysql_fetch_array [message #169806 is a reply to message #169768] Mon, 27 September 2010 12:37 Go to previous messageGo to previous message
matt[1] is currently offline  matt[1]
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Registered: September 2010
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On Sep 25, 4:28 pm, MikeB <mpbr...@gmail.com> wrote:
> I have the following code:
>
> $query = "SELECT * FROM classics";
> $result = mysql_query($query);
>
> if (!$result) die ("Database access failed: " . mysql_error());
> $rows = mysql_num_rows($result);
>
> for ($j = 0 ; $j < $rows ; ++$j)
> {
>         $results[] = mysql_fetch_array($result);
>
> }

This doesn't make much sense to me, unless you need the value of $rows
later on...

how about this instead:

if (!$result = mysql_query("..."))
die ("...");

while ($row = mysql_fetch_array($result))
$results[] = $row;

You're defining two additional variables that are totally unneeded.
Of course some pedant is probably going to jump down my throat for
putting assignments in my conditionals...
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