| Ignoring Case on directories [message #171170] |
Tue, 28 December 2010 20:33  |
jwcarlton
Messages: 76
Registered: December 2010
Karma:
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I think that the answer to this is "no", but I thought I'd ask :-)
I'm wanting to open a file where the directory path is given by the
user. For example:
if (is_file("/path/to/" . $_GET['directory'] . "/file.txt"))
$example = FILE("/path/to/" . $_GET['directory'] . "/file.txt");
else
// return error
// please ignore any typos; I just typed this up here for the example
The thing is, the directory path could be, say, /path/to/SomeDirectory/
file.txt, but the user could enter "somedirectory"; in which case,
they would get the error.
Currently, I keep all of the directory names in a MySQL database, then
before opening file.txt, I search for the directory in MySQL (which is
case insensitive), then load the path based on the name in the
database instead of what's given. But during peak hours, this method
can result in several hundred MySQL queries per minute.
Before this, I just used opendir to load all of the directories into
an array on the fly, then did a case insensitive search through the
array. But, when I started having 90,000 directories (30,000 in 3
separate parent directories), this was considerably slower than using
MySQL.
So, the MySQL search works, but the question is, can PHP do a
directory lookup that's case insensitive; and, preferably, return the
case-correct directory name?
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