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Re: Will this work? [message #172263 is a reply to message #172253] Tue, 08 February 2011 15:25 Go to previous messageGo to previous message
Denis McMahon is currently offline  Denis McMahon
Messages: 634
Registered: September 2010
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Senior Member
On 08/02/11 13:06, Derek Turner wrote:
> On Tue, 08 Feb 2011 01:27:46 +0000, Denis McMahon wrote:
>
>> Note that an empty result set is still a result set!
>>
>> This might be neater, and allows you to use an integer for your loop:
>
> <snip>
>
> Thanks but I'm searching for a string like "02-" so $i needs to be a
> string.
>
> $sql = "SELECT `workName`, `composer`, SUBSTRING(`Reference`,LOCATE(\'08-
> \',`Reference`)) as TRACK FROM `work` WHERE `Reference` LIKE \'%08-%\'
> ORDER BY TRACK";
>
> works fine but I want to search on "01-" ... "99-" stopping when I get a
> zero result. Thanks for the heads-up on zero-result != false, that, and
> your fix are very helpful.

The sprintf makes the integer value into a 2 digit string.

try this:

<?php

$fmt = "Number '%d' rendered as 2 digit string is '%02d'\n";
for ($i = 0; $i < 100; $i++) echo sprintf($fmt,$i,$i);

?>

Rgds

Denis McMahon
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