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Re: terminate a PHP script [message #172591 is a reply to message #172580] Tue, 22 February 2011 02:04 Go to previous messageGo to previous message
sheldonlg is currently offline  sheldonlg
Messages: 166
Registered: September 2010
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On 2/21/2011 8:24 PM, The Natural Philosopher wrote:
> sheldonlg wrote:
>> On 2/21/2011 1:54 PM, n00m wrote:
>>>
>>>> Again, why not if-then-else?
>>>
>>> what if it's 10 nested for() stmts?
>>> And you need to break out of ALL for()'s from the innermost for()?
>>> Do you like 10 if-then-else conditionals, 1 per each for()?
>>
>> && !$exit_all
>>
>> in each of the test conditions of the for loop where $exit_all is
>> initially FALSE outside the outermost loop.
>>
>> for ($i1=0, $exit_all=FALSE; $i1 < $i1_end && !$exit_all; $i1++) {
>> for ($i2=0; $i2 < $i2_end && !$exit_allt; $i2++) {
>> ..... // and so on
>> if ($some_condition == TRUE) {
>> $exit_all = TRUE;
>> break; // or continue which does one extra check step
>> }
>> }
>> }
>>
>>
>>
> I didn't understand a word of that. ;-)

I don't understand why? It is clear as a bell.

> AND you used a BREAK. hanging is too good...

A break is not a goto. Far from it. A break says "stop processing
_this_ particular loop/test". Its scope is _clearly defined_. It
resumes immediately after that loop/test. That is nothing like a goto
which is an unconditional branch to ANYWHERE in the code. (Also, try
writing a switch statement without a break.)

But, if you don't like break here, just leave it out. As it turns out,
in my example the way I wrote it, it is not needed since it is being
tested in the while condition of the loop. It will exit the loop
anyway. The only real reason to have the break in the if test is if
there were some lines of code within that loop after the test.

--
Shelly
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