| Re: Globalizing vars in class methods doesnt seem to work, var disappears after global, var is inaccessible in other methods/funcs [message #178793 is a reply to message #178789] |
Sat, 04 August 2012 18:24   |
Jerry Stuckle
Messages: 2598
Registered: September 2010
Karma:
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Senior Member |
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On 8/3/2012 1:45 PM, J. Frank Parnell wrote:
> <?php
> class test{
> function __construct(){
> $this->makevar();
> global $var;
> echo '<hr>__const(): '.$var;
> }
> function makevar(){
> $var = 'something';
> echo '<hr>just declared in makevar(): '.$var;
> global $var;
> echo '<hr>after global in makevar(): '.$var;
> }
> }//class
>
> $t = new test;
> echo '<hr>outside class: '.$var;
> global $var;
> echo '<hr>outside class after global: '.$var;
>
> ?>
> this outputs:
> just declared in makevar(): something
> after global in makevar(): [nothing]
> __const():[nothing]
> outside class: [nothing]
> outside class after global: [nothing]
>
>
> So, 1, why does global $var in the makevar() make it null?
> and B, why dont I have any access to $var in the __constructor or outside the class?
>
> In the real script, $var will be an instance of a different class that I want to use all over the place.
>
> thanks, J
>
And what if you have:
$t1 = new test;
$t2 = new test;
Which variable are you supposed to be referencing (they are two
different variables)?
But what you're doing violates several concepts in OO programming,
including encapsulation and message passing. The correct way to do it
is to pass an object of the class as a parameter (i.e. to the
constructor) then use getters and setters to reference the variable.
Proper coding makes your code more reliable, maintainable, reusable and
easier to understand.
--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex(at)attglobal(dot)net
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