Re: Multiple <a> Tags, Filled With MySQL DB data with PHP [message #179237 is a reply to message #179232] |
Tue, 25 September 2012 19:16 |
tom.rankin51
Messages: 17 Registered: September 2012
Karma:
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Junior Member |
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I'm way ahead of you. My code is exactly the same regardless of whether I use the PHP or the HTML. My error logs contain absolutely nothing so it doesn't appear to be posting any errors at all.
I honestly thought the above was the bare minimum :-)
I'm pretty exasperated now though with it because it appears I've done everything right?
Tom
On Tuesday, September 25, 2012 7:41:38 PM UTC+1, Denis McMahon wrote:
> On Tue, 25 Sep 2012 10:43:45 -0700, tom.rankin51 wrote:
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>
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>> I am trying to create two image galleries using fancybox. There is no
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>> issue doing this by manually typing out a bunch of <a> tags with the
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>> info inside, but when I attempt to code a piece of PHP to pull this data
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>> from my database, it doesn't like it and displays the images strangely.
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>
>
> Basic troubleshooting for php / mysql / html stuff:
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>
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> 1) Turn all the warnings on in php
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> 2) Make sure that every database call tests for errors, and that they get
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> reported
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> 2a) In extreme cases, output the actual sql query and var_dump the result:
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>
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> I do something like this at the top of my code in such situations:
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> <?php
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> $debugtxt = "";
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> $debugging = false;
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> if ( $_SERVER['REMOTE_ADDR'] == $my_ip && $_GET['debug'] == "37" )
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> $debugging = true;
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>
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> ?>
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>
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> and wrap something like this round every sql call:
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>
>
> <?php
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> $sql = ".......";
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>
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> $result = mysqli->query( $sql );
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>
>
> $debugtxt .= "sql call to get date of last login from users table\n";
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> $debugtxt .= "sql: {$sql}\n";
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> $debugtxt .= "Result:" . var_dump( $result );
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>
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> if ( $result === false ) {
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> ..... do onething
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> }
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> else {
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> ..... do otherthing
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> }
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> ?>
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> When you generate the html, before the closing </body> tag:
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>
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> <?php if ( $debugging ) echo "<hr><h1>Debugging</h1><pre>$debugtxt</pre>
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> \n"; ?>
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>
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> 3) check the server error logs after each request
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> 4) view the html source of the pages you get so you can see the actual
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> html that your page is generating
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> 5) When posting to the group, pare your code down to the minimum that
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> demonstrates the problem.
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>
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> You will hopefully then be able to determine where your code is going
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> wrong and why.
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> In this particular case, I would suggest (4) is particularly important,
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> you have told us what you expect, and what code you use to generate it,
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> but have not shown us what the generated html looks like when examined
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> with the source viewer in your browser.
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>
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> If no html is generated, go back to the server logs looking for a php
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> reported error. If your sql query is failing, your sql result set is
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> actually the value false, and you're failing to detect this. There may be
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> an sql error message in your server logs.
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>
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> Rgds
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>
>
> Denis McMahon
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