Re: Multiple <a> Tags, Filled With MySQL DB data with PHP [message #179239 is a reply to message #179228] |
Tue, 25 September 2012 20:02 |
Jerry Stuckle
Messages: 2598 Registered: September 2010
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Senior Member |
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On 9/25/2012 2:26 PM, tom(dot)rankin51(at)googlemail(dot)com wrote:
> On Tuesday, September 25, 2012 7:21:50 PM UTC+1, Jerry Stuckle wrote:
>> On 9/25/2012 1:43 PM, tom(dot)rankin51(at)googlemail(dot)com wrote:
>>
>>> Hello
>>
>>>
>>
>>> I am trying to create two image galleries using fancybox. There is no issue doing this by manually typing out a bunch of <a> tags with the info inside, but when I attempt to code a piece of PHP to pull this data from my database, it doesn't like it and displays the images strangely.
>>
>>>
>>
<snip code>
>>> Now, I think that this should do exactly the same thing, other than showing four thumbnails obviously. What actually happens is that the first thumbnail loads the last added image in a new page, then the other three as expected but with the focus on the picture displayed by the query. It also did not show a Facebook share button when using PHP.
>>
>>>
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>>> I understand that this issue isn't all down to PHP, but may be down to the fancybox script. However, I can't post in two groups simultaneously so if my code looks correct then I can go along another route.
>>
>>>
>>
>>> Thanks in advance
>>
>>> Tom
>>
>>>
>>
>>
>>
>> Look at the source code in your page - does it look correct?
>>
>>> I'm not sure what you mean. I think my source is correct yes, hence
why I can't figure out the problem. As far as my knowledge extends, the
php code I provided does exactly the same as the collection of <a> tags
- but it produces completely different results.
>
> I have already noted that my php code will produce four thumbnails
which I have accounted for, however it i this code which will load the
first image in a new page and not display facebook share links.
>
> Tom
>
(top posting fixed)
I mean look at the generated HTML - in your browser, "View Source".
Compare it to what works.
It obviously is NOT correct, or it would generate the desired results.
Also, you should NOT use the '@' character on your MySQL (or any other)
calls. It will hide any possible warning or error messages you get.
P.S. Please don't top post. Thanks.
--
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Jerry Stuckle
JDS Computer Training Corp.
jstucklex(at)attglobal(dot)net
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