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Re: Multiple <a> Tags, Filled With MySQL DB data with PHP [message #179247 is a reply to message #179246] Tue, 25 September 2012 23:48 Go to previous messageGo to previous message
Jerry Stuckle is currently offline  Jerry Stuckle
Messages: 2598
Registered: September 2010
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Senior Member
On 9/25/2012 7:19 PM, Denis McMahon wrote:
> On Tue, 25 Sep 2012 22:12:43 +0200, Luuk wrote:
>
>> On 25-09-2012 21:58, tom(dot)rankin51(at)googlemail(dot)com wrote:
>>> I'm not too sure how to debug correctly following these instructions.
>>> I can place the code at the beginning and end of my page, but I am
>>> getting a syntax error when typing $result = mysqli->query($sql);
>>>
>>>> <?php $sql = ".......";
>>>> $result = mysqli->query( $sql );
>>
>>>> $debugtxt .= "sql: {$sql}\n";
>>
>> or, that last one could be:
>> echo "SQL: {$sql}\n";
>>
>> it should echo the query to the output......
>
> Yeah, but when I'm trying to debug code generating a web page, I stick
> all the debugging output in a <pre> element at the end of the page, if I
> don't get the pre element output the problem is invariably identified in
> the server error log.
>
> To the OP - sorry, you're not using mysqli .... replace "$result = mysqli-
>> exec( $sql );" with whatever code you're using to make your database
> call, maybe the "mysql_query" call.
>
> Change this php:
>
> $visuals_query=mysql_query("SELECT id, imagelink, comment, picdate, rel
> FROM PictureMedia ORDER BY picdate DESC");
>
> To:
>
> <?php
> $sql = "SELECT id, imagelink, comment, picdate, rel FROM PictureMedia
> ORDER BY picdate DESC";
> $visuals_query=mysql_query( $sql );
> $debug = "sql: " $sql . "\nresult: " . var_dump( $visuals_query ) . "\n";
> if ( $visuals_query == false )
> $debug .= "sql error: " . mysql_error() . "\n";
> ?>
>
> and then use the
>
> <?php echo "<php>{$debug}</pre>"; ?>
>
> to show the actual query, the query result set (warning, can be large)
> and any sql error messages.
>
> Rgds
>
> Denis McMahon
>

Won't show much. The result of a mysql_query call is a result, not an
array. All it will say is "false" or "resource id 2" (or similar). And
your following "if" statement will handle the first result.

--
==================
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Jerry Stuckle
JDS Computer Training Corp.
jstucklex(at)attglobal(dot)net
==================
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