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Re: Beginner's trouble with substr [message #179456 is a reply to message #179455] Mon, 29 October 2012 17:40 Go to previous messageGo to previous message
C is currently offline  C
Messages: 24
Registered: January 2012
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On 29 loka, 19:34, Salvatore <s...@yojimbo.hack.invalid> wrote:
> On 2012-10-29, wrong.addres...@gmail.com <wrong.addres...@gmail.com> wrote:
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>> What am I doing wrong in this? The substr part does not seem to get processed properly.
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>> <?php
>
>> global $host;
>> $host=@gethostbyaddr($REMOTE_ADDR);
>> if ($HTTP_SERVER_VARS["HTTP_X_FORWARDED_FOR"] != "")
>>    {$realhost = @gethostbyaddr($HTTP_SERVER_VARS["HTTP_X_FORWARDED_FOR"]);}
>> $referer = $HTTP_REFERER;
>
>> if (substr($host, -3) == ".xy") {exit;} //
>> if (substr($host, 6) == "abcd29") {exit;} //
>> if (substr($referer, -4) == ".xyz") {exit;} //
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>> if ($found == 1) {include 'simple.html';} else {include 'home.html';}
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>> ?>
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> The first thing I see wrong is that the variable "$found" is not
> declared.
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> What are you trying to achieve?
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> --
> Blah blah bleh...
> GCS/CM d(-)@>-- s+:- !a C++$ UBL++++$ L+$ W+++$ w M++ Y++ b++

I took that code out which defines $found. The code is trying to avoid
some nasty visitors.
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