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Re: Beginner's trouble with substr [message #179458 is a reply to message #179454] Mon, 29 October 2012 20:44 Go to previous messageGo to previous message
Doug Miller is currently offline  Doug Miller
Messages: 171
Registered: August 2011
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wrong(dot)address(dot)1(at)gmail(dot)com wrote in news:c67eb83e-13d8-4263-b723-a10744fcd444
@googlegroups.com:

>
> What am I doing wrong in this? The substr part does not seem to get processed properly.

That is because you are not using it properly.
http://us3.php.net/manual/en/function.substr.php

The second parameter is the starting position, not (as you appear to believe) the length;
length is the *third* parameter.

>
> <?php
>
> global $host;
> $host=@gethostbyaddr($REMOTE_ADDR);
> if ($HTTP_SERVER_VARS["HTTP_X_FORWARDED_FOR"] != "")
> {$realhost = @gethostbyaddr($HTTP_SERVER_VARS
["HTTP_X_FORWARDED_FOR"]);}
> $referer = $HTTP_REFERER;
>
> if (substr($host, -3) == ".xy") {exit;} //
> if (substr($host, 6) == "abcd29") {exit;} //
> if (substr($referer, -4) == ".xyz") {exit;} //
>
> if ($found == 1) {include 'simple.html';} else {include 'home.html';}
>
> ?>
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