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Re: comparing arrays [message #181052 is a reply to message #181045] Sun, 07 April 2013 15:13 Go to previous messageGo to previous message
Thomas 'PointedEars'  is currently offline  Thomas 'PointedEars'
Messages: 701
Registered: October 2010
Karma:
Senior Member
Frank Steinmetzger wrote:

> bill wrote:
>> On 4/7/2013 8:34 AM, Jerry Stuckle wrote:
>>> On 4/7/2013 7:34 AM, bill wrote:
>>>> I need to see if a patient has appointments with a psychotherapist
>>>> and a physician on the same day.
>>>>
>>>> I request the schedule of each therapist and each physician as
>>>> arrays of arrays:
>>>> time, patient_number, duration (note, the therapist/physician
>>>> id is not in the array)
>>>> They are non-associative arrays (numeric keys)
>>>> I might have 1..n physicians and 1..n therapists
>>>> I can generate arrays of physicians and arrays of therapists
>>>> […]
>>>>
>>> Does the information come from a SQL database? If so, I'd do it
>>> in SQL.
>>
>> Yes it does, 3 tables: users (therapist/physician), pt_info,
>> schedule.
>>
>> A little more of a hint please.
>
> You select two different appointments that have the same date:
>
> SELECT s1.patient_number AS pn, s1.time AS t1, s2.time AS t2,
> s1.duration AS d1, s2.duration AS d2
> FROM schedule s1, schedule s2
> WHERE s1.time=s2.time AND s1.time=<today's date>
> AND s1.patient_number=s2.patient_number
> AND s1.patient_number=<ID of patient of interest>
> AND s1.id!=s2.id
> AND s1.doctor_number!=s2.doctor_number

Please don't. If each schedule table has as little as 100 records, there
will be 10'000 result records to filter from. Read on JOIN to avoid
Cartesian products like this.

> Of course, those times don't work that way, b/c they have date *and* time,
> and you want to deal with date only. I'm not into advanced SQL,

Apparently you are not into SQL, or relational databases for that matter, at
all.

> perhaps there is an SQL function to only extract and use the date part.

QED.

> You then would need to PHP-fiddle the time and duration together for only
> those appointments that are today in a nested for-loop.

No. Apparently you are also not into PHP.

Please refrain from suggesting “solutions” in areas where you do not have a
(minimum) clue. TIA.


PointedEars
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