| Re: Setting & displaying Variables [message #182869 is a reply to message #182864] |
Sun, 22 September 2013 20:54   |
bill
Messages: 310
Registered: October 2010
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Senior Member |
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On 2013-09-21 5:29 PM, Richard Yates wrote:
> On Sat, 21 Sep 2013 16:20:49 -0400, Twayne <nobody(at)spamcop(dot)net> wrote:
>
> Probably those three Ms in '$commments'
3 M's? You're kidding!! I'd love to think that's a typo, but ... I
pasted, not copied, the code, sooo ... Ohh, I might be about to feel so
stoopid!
You know, I still didn't see it even after you pointed it out! Had to
use Find to see it! Damn! I'm going to owe you bigtime if that's all it
is! :(
I'll let ya know!
Twayne`
>
>
>> Hi,
>>
>> Obviously, the issue is around the comments var. It works, but it
>> doesn't and I'm hoping someone can explain why.
>>
>> Both echo strlen($comments); and echo $comments; throw a Notice
>> about an undefined variable. But the variable "comments" HAS to have
>> been defined in order for the two echo statements to work!
>> The variable 'comments' is also in SESSION data, which will also get
>> the same Notice of an undefined variable.
>>
>> What the heck am I missing? Why do I get the undefined var in those two
>> statements?
>>
>> ===================
>> <code>
>> echo strlen($_POST["comments"])."<br />"; //WORKS
>>
>> $commments = $_POST["comments"]; // WORKS but not needed; done elsewhere
>> too.
>>
>> // echo strlen($comments); // GETS Notice: Undefined variable: comments
>> in C:\xampp\htdocs... and nothing displays.
>>
>> echo $_POST["comments"]; // WORKS
>> //echo $comments; // GETS Notice: Undefined variable: comments in C
>> ... and nothing displays.
>>
>> </code>
>> ===================
>>
>> I'm obviously missing something here since it appears the var is set
>> according to the 2 statements that do display what I expected. Can you
>> straighten me out? I've had this happen before with other vars and it's
>> always confusing.
>>
>> TIA,
>>
>> Twayne`
>>
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