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Operator precedence [message #184990] Sun, 23 February 2014 17:03 Go to previous message
Christoph Michael Bec is currently offline  Christoph Michael Bec
Messages: 207
Registered: June 2013
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Senior Member
I've stumbled upon the following code:

!$a && $a = 42;

Apparently, this is meant instead of

if (!$a) $a = 42;

or

!$a AND $a = 42;

However, I am quite confused that it works because the = operator has
lower precendence than the && operator[1]. Actually that should mean
the statement is equivalent to

(!$a && $a) = 42;

But this obviously won't work.

Why does the mentioned statement has the "expected" result? Is it
reliable to write it that way?

[1] <http://www.php.net/manual/en/language.operators.precedence.php>

--
Christoph M. Becker
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