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Re: count() problem [message #185712 is a reply to message #185709]

Sat, 03 May 2014 22:14

Denis McMahon
Messages: 634
Registered: September 2010

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Senior Member

On Sat, 03 May 2014 15:57:26 -0400, richard wrote:

> On Sat, 03 May 2014 20:32:56 +0200, M. Strobel wrote:
>
>> Am 03.05.2014 20:18, schrieb richard:
>>>
>>> $dir = '../audio/'.$yr.'/';
>>> $files = scandir($dir); $number=count(files);
>> did you mean
>> $number=count($files);
>> ?
>> /Str.
>>> echo $number;
>>>
>>> Why does this always show the resutlt as 1?
>>>
>>>
>>> $dir = '../audio/'.$yr.'/';
>>> $files = scandir($dir);
>>> echo count(files);
>>>
>>> Shows the true count of the array.

> thanks. many times I overlook the obvious.

Did you even think to check for any warning messages? Did you have
warnings turned on? PHP will usually generate a warning if warnings are
on and you appear to have left a $ off of a variable name.

--
Denis McMahon, denismfmcmahon(at)gmail(dot)com

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[Message index]

		count() problem By: Mr Oldies on Sat, 03 May 2014 18:18
		Re: count() problem By: M. Strobel on Sat, 03 May 2014 18:32
		Re: count() problem By: Mr Oldies on Sat, 03 May 2014 19:57
		Re: count() problem By: Denis McMahon on Sat, 03 May 2014 22:14
		Re: count() problem By: Richard Yates on Sat, 03 May 2014 18:33
		Re: count() problem By: M. Strobel on Sat, 03 May 2014 18:36

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